it is 11.25................................
Answer:
Step-by-step explanation:
You divide 3 from both sides leaving you with g=(x/3)-(2/3)
Please mark my answer as brainlyest.
Answer:
Number of dimes = 16
Number of quarters = 17
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Work Shown:
d = number of dimes
q = number of quarters
d+q = 33 coins total, this solves to d = 33-q
10d = value of all the dimes in cents
25q = value of all the quarters in cents
10d+25q = 585 cents total
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Plug in d = 33-q and solve for q
10d+25q = 585
10(33-q) + 25q = 585
330-10q+25q = 585
15q+330 = 585
15q = 585-330
15q = 255
q = 255/15
q = 17
The man has 17 quarters
d = 33-q = 33-17 = 16
He also has 16 dimes.
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Check:
16 dimes + 17 quarters = 33 coins total
16 dimes = 16*10 = 160 cents
17 quarters = 17*25 = 425 cents
160 cents + 425 cents = 585 cents
The answer is confirmed.
Answer:
a). 0.294
b) 0.11
Step-by-step explanation:
From the given information:
the probability of the low risk = 0.60
the probability of the high risk = 0.40
let 
represent no claim
let 
represent 1 claim
let 
represent 2 claim :
For low risk;
so, = (0.80 * 0.60 = 0.48), = (0.15* 0.60=0.09), = (0.05 * 0.60=0.03)
For high risk:
= (0.50 * 0.40 = 0.2), = (0.30 * 0.40 = 0.12) , = ( 0.20 * 0.40 = 0.08)
Therefore:
a), the probability that a randomly selected policyholder is high-risk and filed no claims can be computed as:
b) What is the probability that a randomly selected policyholder filed two claims?
the probability that a randomly selected policyholder be filled with two claims = 0.03 + 0.08
= 0.11
(4xy - 3z)²
(4xy - 3z)(4xy - 3z)
4xy(4xy - 3z) - 3z(4xy - 3z)
16x²y² - 12xyz -12xyz + 9z²
16x²y² - 24xyz + 9z², a perfect square trinomial.
