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Nikitich [7]
3 years ago
13

Complete the sentences.

Mathematics
1 answer:
Alex73 [517]3 years ago
7 0
<h3>Answer:</h3>
  • years 1–4: 62.4 bass per year
  • years 5–8: 67.6 bass per year
<h3>Step-by-step explanation:</h3>

If the population in year n is ...

  p(n) = 3000·1.02^n

then the average rate of change from year 1 to year 4 is ...

  (p(4) -p(1))/(4 -1) = 3000(1.02^4 -1.02^1)/3 = 1020·(1.02^3 -1) ≈ 62.4

The average rate of change for years 1–4 is 62.4 bass per year.

___

For years 5–8, the rate of change is similarly computed:

  (p(8) -p(5))/(8 -5) = 3000(1.02^8 -1.02^5)/3 = 1000·1.02^5·(1.02^3 -1) ≈ 67.6

The average rate of change for years 5–8 is 67.6 bass per year.

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PLEASE AWNSEERRRRRRRRRRR wILL GIVE BRANILIEST
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Step-by-step explanation:

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6=5-4+(3*2)-1;

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14=(5+4+3+2)*1;

15=5+4+3+2+1;

16=5+4+(3*2)+1;

17=5+(4*3)*(2-1);

18=5+(4*3)+2-1;

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20=(5*4)-3+2+1;

21=(5*4)+3-(2*1);

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26=(5*4)+3+2+1;

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32=5*(4+3)-2-1;

33=5*(4+3)-(2*1);

34=5*(4+3)-2+1;

35=5*(4+3)*(2-1);

36=5*(4+3)+2-1;

37=5*(4+3)+(2*1);

38=5*(4+3)+2+1;

(no equation for 39);

40=5*(4+3+2-1)

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Thus, 40+30s=220

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