-6,-7, and -8, this is more of a guess and check question
Answer:
Part 1) Option D. must be an acute angle
Part 2) m∠A=70°
Step-by-step explanation:
Part 1) In triangle ABC, if an exterior angle drawn at vertex C measures 45, then angle B...
we know that
An exterior angle of a triangle is equal to the sum of the opposite interior angles
so
The measure of an exterior angle at C is equal to the sum of the interior angles at A and B
we have that
45°=m∠A+m∠B
therefore
m∠B < 90°
Angle B must be an acute angle
Part 2)
we know that
An exterior angle of a triangle is equal to the sum of the opposite interior angles
so
The measure of an exterior angle at B is equal to the sum of the interior angles at A and C
m∠A+m∠C=2m∠C+5
m∠C=m∠A-5 ----> equation A
m∠C=65° ----> equation B
substitute equation B in equation A
65°=m∠A-5
m∠A=(65+5)°=70°
Answer: (y-c)/m
Reasoning:
Subtract c from both sides [ y-c=mx+c-c ]
Divide m from both sides [ (y-c)/m=mx/m ]
Answer:
y = 8x+0
Step-by-step explanation:
The slope is
m = (y2-y1)/(x2-x1)
= (-8-0)/(-1-0)
-8/-1
8
The y intercept is 0 since it goes through (0,)
The slope intercept form of the equation is
y = mx+b
y = 8x+0
Answer:
36.1g
Step-by-step explanation:
29mi ..... 1 g
1047mi....x
x=1047×1/29=36.1g
