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VARVARA [1.3K]
3 years ago
9

What is the value of a? 14 – 2a = 4a – 16

Mathematics
2 answers:
VladimirAG [237]3 years ago
3 0
14 - 2x = 4a - 16

First, add 2a to both sides. / Your problem should look like: 14 = 4a - 16 + 2a
Second, simplify 4a - 16 + 2a to get 6a - 16. / Your problem should look like: 14 = 6a - 16
Third, add 16 to both sides. / Your problem should look like: 14 + 16 = 6a
Fourth, add 14 + 16 to get 30. / Your problem should look like: 30 = 6a
Fifth, divide both sides by 6. / Your problem should look like: \frac{30}{6}  = a
Sixth, 6 goes into 5 to get 30, so simplify \frac{30}{6} to 5. / Your problem should look like: 5 = a
Seventh, switch your sides. / Your problem should look like: a = 5

Answer: a = 5
fiasKO [112]3 years ago
3 0

14−2a=4a−16

14+−2a=4a+−16

−2a+14=4a−16

Subtract 4a from both sides.

−2a+14−4a=4a−16−4a

−6a+14=−16

Subtract 14 from both sides.

−6a+14−14=−16−14

−6a=−30

Divide both sides by -6.

−6a/−6=−30/−6

a=5

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Step-by-step explanation:

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An angle measures 16.4° less than the measure of its supplementary angle. What is the measure of each angle?
Black_prince [1.1K]

Answer:

Step-by-step explanation:

Let one angle = A

Let the other angle = B

A + B = 180

A = B - 16.4                   Substitute for A in the top equation

B - 16.4 + B = 180         Combine the left

2B - 16.4 = 180             Add 16.4 to both sides

2B = 180 + 16.4

2B = 196.4                    Divide by 2

B = 196.4/2

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3 years ago
HELP ILL GIVE BRAINLIEST QUICKK
ehidna [41]

Answer:

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Step-by-step explanation:

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3 years ago
Find the area of the composite figure.
Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

\boxed{\rm \: Breadth = total  \: distance - Radius}

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

\longrightarrow\rm \: Length \:  of \:  the  \: circle = Radius

  • Since Length = 6 in ;

\longrightarrow \rm \: 6 \: in   = radius

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

  • Total Horizontal Distance= 14
  • Radius = 6

\longrightarrow\rm \: Breadth = 14-6

\longrightarrow\rm \: Breadth = 8 \: in

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

  • Length = 6
  • Breadth = 8

\longrightarrow\rm \: Area \:  of  \: Rectangle = 6 \times 8

\longrightarrow \rm \: Area \:  of  \: Rectangle = 48 \: in {}^{2}

Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

  • r = radius = 6
  • π = 3.14

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9

\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

  • \rm Area_{(rectangle)} = 48
  • \rm Area_{(Quarter Circle)} = 28.26

\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

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Trava [24]

Answer:

ion even know

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