What is the face value of 2 in the number 286?
2 answers:
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Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;
Seperate the differential equation and solve for the constant C.
You have 100 rodents when:
You have 1000 rodents when:
Answer:
Step-by-step explanation:
pythagoras theorem
a^2+b^2=c^2
8^2+x^2=10^2
64+x^2=100
x^2=100-64
x=
x=6 km