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2 years ago

During your cycling trip, you and your friends often stayed in hostels. The prices of these are listed below.

Mathematics

1 answer:

kiruha [24]2 years ago

7 0

Answer:

a) NTRD standard price = $26.30
b) range: $11.20 to $33.00, a range of $21.80

Step-by-step explanation:

a) The average is the sum divided by the number of contributors. Let n represent the standard price at Night-Time Rest Days. Then ...

... ($22.45 +18.55 +24.50 +11.20 +n)/5 = $20.60

... 76.70 + n = 103.00 . . . . multiply by 5 and collect terms

... n = $26.30 . . . . standard price at NTRD

b) The lowest standard price is $11.20. The highest breakfast price is $33.00. The range is the difference between these ...

... $33.00 -11.20 = $21.80 . . . . range in cost for a single night

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Marcos drops a bouncy ball from a hieght of 40 feet. The ball loses 10% of its maximum height on each bounce. How high will it b

iren [92.7K]

I think after the 9th bounce it will lose 90% of its max height

times 40 by 0.9 which will give you 36
then take 36 away from 40 leaving you with 4.

answer = 4ft

4 0

2 years ago

A explanation also would be super helpful and very appreciated!

xxTIMURxx [149]

Answer:

26%

Step-by-step explanation:

345. 24 - 274 = 71.24

71.24 / 274 =0.26

0.26 * 100 = 26

8 0

3 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

2 years ago

Water pours into a tank at the rate of 2000 cm3/min. The tank is cylindrical with radius 2 meters. How fast is the height of wat

Gennadij [26K]

Volume of water in the tank:

$V=\pi (2\,\mathrm m)^2h=\pi(200\,\mathrm{cm})^2h$

Differentiate both sides with respect to time t :

$\dfrac{\mathrm dV}{\mathrm dt}=\pi(200\,\mathrm{cm})^2\dfrac{\mathrm dh}{\mathrm dt}$

V changes at a rate of 2000 cc/min (cubic cm per minute); use this to solve for dh/dt :

$2000\dfrac{\mathrm{cm}^3}{\rm min}=\pi(40,000\,\mathrm{cm}^2)\dfrac{\mathrm dh}{\mathrm dt}$

$\dfrac{\mathrm dh}{\mathrm dt}=\dfrac{2000}{40,000\pi}\dfrac{\rm cm}{\rm min}=\dfrac1{20\pi}\dfrac{\rm cm}{\rm min}$

(The question asks how the height changes at the exact moment the height is 50 cm, but this info is a red herring because the rate of change is constant.)

7 0

2 years ago

Help me on this i will give brainliest to the first answer

noname [10]

Answer:

I would say try D and then try A

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers