All categories

2 years ago

HELPPPPPPPPPPPPPPPOO

Mathematics

1 answer:

AURORKA [14]2 years ago

8 0

To do the comparison, we'll use the following temperatures:

Day 1: 5°F

Day 2 : 1.5°F

Comparison of Day 1 and Day 2:

$1.5F$

$5F>1.5F$

Comparison of days with absolute value:

$1.5F$

$5F>1.5F$

The temperature that's the closest to 0 during the week is -0.5°F. Using absolute value, we can see that the distance from 0°F to -0.5°F is the smallest of all the temperature measurements.

The temperature that's the farthest to 0 during the week is 5°F. Using absolute value, we can see that the distance from 0°F to 5°F is the biggest of all the temperature measurements.

The coldest temperature is -4°F. This is the value that is farthest to the left of 0°F on the number line.

The warmest temperature is 5°F. This is the value that is farthest to the right of 0°F on the number line.

You might be interested in

What must you invest today to receive an annuity of $4,500 for 10 years compounded at 8% quarterly when all withdrawals will be

OlgaM077 [116]

Answer:

Kent is making a scale model of his favorite train. The actual train is 12 feet long and 4 feet wide. Kent wants his model to be 6 inches in length. Which would if he uses the same ratio?

Step-by-step explanation:

Kent is making a scale model of his favorite train. The actual train is 12 feet long and 4 feet wide. Kent wants his model to be 6 inches in length. Which would be the width if he uses the same ratio?

6 0

3 years ago

Ok so this is so confusing The volume of water in a rectangular swimming pool can be modeled by the polynomial 2x3 _ 9x2 + 7x +

Alika [10]

The volume formula is V= l x L x H, l=width, L=Length, H= Depth, so
2x3 _ 9x2 + 7x + 6 = l x L x (2x + 1), because H=(2x + 1), so
l x L= (2x3 _ 9x2 + 7x + 6 )/ (2x + 1) = (2x3 _ 9x2 + 7x + 6 ) X [1/(2x + 1)]
case1: l= (2x3 _ 9x2 + 7x + 6 ) or L= 1/(2x + 1), case2: L= (2x3 _ 9x2 + 7x + 6 ) or l= 1/(2x + 1)
the why question:
perhaps there is similarity of value between volume and l, or volume and L

6 0

3 years ago

Simplify –3 – 1 what is the answer to this ?

QveST [7]

Answer:

-4

Step-by-step explanation:

-3-1= -4

A negative minus a positive= a "larger" positive.

5 0

3 years ago

Solve this expression 8÷2*5+(6-4)

Annette [7]

Value of expression $\frac{8}{2}(5) + (6-4)$ is 22 .

<u>Step-by-step explanation:</u>

Here we have the following expression to solve :

8÷2*5+(6-4)

⇒ $(8/2)*5 + (6-4)$

⇒ $\frac{8}{2}(5) + (6-4)$

But 8 = 4(2) , So

⇒ $\frac{4(2)}{2}(5) + (6-4)$

⇒ $4(5) + (6-4)$

⇒ $20 + (6-4)$

⇒ $20 + 2$

⇒ $22$

Therefore, Value of expression $\frac{8}{2}(5) + (6-4)$ is 22 .

6 0

3 years ago

An automobile manufacturer finds that 1 in every 2500 automobiles produced has a particular manufacturing defect. (a) Use a bin

Advocard [28]

Answer:

a) 0.1558 = 15.58% probability of finding 4 cars with the defect in a random sample of 7000 cars.

b) 0.1557 = 15.57% probability of finding 4 cars with the defect in a random sample of 7000 cars. These probabilities are very close, which means that the approximation works.

Step-by-step explanation:

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

To use the Poisson approximation for the binomial, we have that:

$\mu = np$

1 in every 2500 automobiles produced has a particular manufacturing defect.

This means that $p = \frac{1}{2500} = 0.0004$

a) Use a binomial distribution to find the probability of finding 4 cars with the defect in a random sample of 7000 cars.

This is $P(X = 4)$ when $n = 7000$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{7000,4}.(0.0004)^{4}.(0.9996)^{6996} = 0.1558$

0.1558 = 15.58% probability of finding 4 cars with the defect in a random sample of 7000 cars.

(b) The Poisson distribution can be used to approximate the binomial distribution for large values of n and small values of p.

Using the approximation:

$\mu = np = 7000*0.0004 = 2.8$ . So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 4) = \frac{e^{-2.8}*(2.8)^{4}}{(4)!} = 0.1557$

0.1557 = 15.57% probability of finding 4 cars with the defect in a random sample of 7000 cars. These probabilities are very close, which means that the approximation works.

6 0

3 years ago