Just think about this. 35 + ( 20 * y ) I'm not really sure but this is the best I can do.
Answer:
Step-by-step explanation:
Length = 4
Width = 3
h = height
distance(d) = ![\sqrt{34}](https://tex.z-dn.net/?f=%5Csqrt%7B34%7D)
To find distance you use this equation: ![d=\sqrt{l^2+w^2+h^2}\\](https://tex.z-dn.net/?f=d%3D%5Csqrt%7Bl%5E2%2Bw%5E2%2Bh%5E2%7D%5C%5C)
So since you already have to distance you can plug in the variable you do have and solve it backwards to get the height.
![\sqrt{34}=\sqrt{4^2+3^2+h^2} \\34=4^2+3^2+h^2\\34=16+9+h^2\\ 34=25+h^2\\ 9=h^2\\ \sqrt{9}=\sqrt{h^2} \\3=h](https://tex.z-dn.net/?f=%5Csqrt%7B34%7D%3D%5Csqrt%7B4%5E2%2B3%5E2%2Bh%5E2%7D%20%20%5C%5C34%3D4%5E2%2B3%5E2%2Bh%5E2%5C%5C34%3D16%2B9%2Bh%5E2%5C%5C%2034%3D25%2Bh%5E2%5C%5C%209%3Dh%5E2%5C%5C%20%5Csqrt%7B9%7D%3D%5Csqrt%7Bh%5E2%7D%20%20%5C%5C3%3Dh)
For this kind of exercise you need to know the trigonometric identities.
In this case:
--->sin(2a)=2(sen(a)*cos(a))
(That comes from sin(a+b)=sin(a)*cos(b)+cos(a)*sin(b), since 2a is just a sum a a+a)
--->sin^2(a)+cos^2(a)=1
That way you can start transforming things and simplifying.
By doing that I got to: 2sin(x)*cos^2(x) (or 2sin(x)-2sin^3(x))
I attached the steps I followed as an image (I made a mistake on paper at the very end, that's a multiplication not a substraction, it's 2sin(x)*cos^2(x))