All categories

3 years ago

Plz help me!!!!

Mathematics

1 answer:

sveta [45]3 years ago

4 0

A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.

b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>

You might be interested in

Number 20. if a and b are integers and a > b, then l a l > l b l

raketka [301]

. Answer: I am pretty sure sometimes

Step-by-step explanation: if a = 6 and B = - 7, if you put them l a l > | b |

It makes them both positive so sometimes is the most probable answer .

( Sorry if it’s wrong)

6 0

3 years ago

Read 2 more answers

Amy, a nature photographer, randomly sampled photographs she took within the last year. She wanted to find out how many of her p

Sveta_85 [38]

The Constructed confidence interval for the proportion of her photographs taken within the last year contained flowers is

$CI\ E(0.57,0.65)$

From the question we are told that:

The proportion of photographs that had flowers P= 0.61

Margin of error of M.E= 0.04

Generally, the equation for Confidence interval for proportion is mathematically given by

$CI=0.61 \pm 0.04$ P \pm M.E

Therefore Confidence interval is

$CI=0.61 \pm 0.04$

And can also be written as

$CI\ E((0.61+0.04),0.61-0.04))$

$CI\ E(0.57,0.65)$

In conclusion the Confidence interval is

$CI\ E(0.57,0.65)$

For more information on this visit

brainly.com/question/24131141?referrer=searchResults

4 0

3 years ago

an administrator is asked to file papers in a box which has the following dimensions:height 15cm, width 300mm and depth 0.2m. ca

nalin [4]

Answer:

900cm^3

Step-by-step explanation:

1 cm= 10 mm

x=300mm (criss cross)

1cm*300mm/10mm= 10mm*x/10mm

30cm=x

30cm=300mm

1m=100cm

0.2m=x

1m*x/1m=0.2m*100cm/1m

x=0.2*100cm

x=20cm

0.2m=20cm

l=15cm

w=30cm

h=20cm

v=l*w*h

v=15cm*30cm*20cm

v=450cm^2*20cm

v=900cm^3

6 0

3 years ago

Read 2 more answers

A certain book has 200 pages, and 47 of these pages have an illustration. If one of the book's pages

Ugo [173]

Answer: fraction:47/200 desimal:0.235

Step-by-step explanation:

6 0

3 years ago

How do you reduce 2 1/32

wlad13 [49]

Answer:

I don't think you can reduce this number.

Step-by-step explanation:

There is no common factor between the numbers. Thus it stays the same. Hope this helps .

6 0

3 years ago