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stellarik [79]
3 years ago
5

Please Help! what is g(x)?​

Mathematics
1 answer:
Illusion [34]3 years ago
7 0

Answer:

The answer is option B.

g(x) = - x²

Hope this helps you

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What is 2 divided by 3 written as fractions?
Pachacha [2.7K]

1/3 with a line over the answer ( 0.66666666666...)

4 0
3 years ago
How should I tell my crush I like her? She's my friend and I asked her if she liked me yesterday and she said no but I think she
Helen [10]

Answer:

U just have to make her feel comfortable to trust u that she can tell u that she actually likes u....dont push anything just make her feel appreciated ok?

Step-by-step explanation:

that's all

4 0
3 years ago
A family is relocating from St. Louis, Missouri, to California. Due to an increasing inventory of houses in St. Louis, it is tak
Dafna1 [17]

Answer:

a. Assume that the population has a normal distribution.

b. The 90% confidence interval of the mean sale time for all homes in the neighborhood is between 219.31 days and 240.69 days.

Step-by-step explanation:

Question a:

We have to assume normality.

Question b:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645\frac{35}{\sqrt{29}} = 10.69

The lower end of the interval is the sample mean subtracted by M. So it is 230 - 10.69 = 219.31 days.

The upper end of the interval is the sample mean added to M. So it is 230 + 10.69 = 240.69 days.

The 90% confidence interval of the mean sale time for all homes in the neighborhood is between 219.31 days and 240.69 days.

7 0
3 years ago
Suppose the total area is represented by the equation x^2+14x+24. If the area 1 is x^2 square units and area IV is 24 units, wha
Nutka1998 [239]

Answer:

See Explanation

Step-by-step explanation:

Given

Total = x^2 + 14x + 24

Area\ I = x^2

Area\ IV = 24

Required

True about area II and III

The question is incomplete; so, I will answer using general knowledge.

If the total area is:

Total = x^2 + 14x + 24

And there are 4 areas, then;

Total = Area\ I + Area\ II + Area\ III + Area\ IV

Rewrite as:

Total = Area\ I + Area\ IV+ Area\ II + Area\ III

This gives:

x^2 + 14x + 24 = x^2 + 24+ Area\ II + Area\ III

Collect like terms

x^2 -x^2 + 14x + 24 -24=  Area\ II + Area\ III

14x =  Area\ II + Area\ III

Rewrite as:

Area\ II + Area\ III  = 14x

<em>So, the sum of areas III and IV must be 14x</em>

4 0
3 years ago
David kicks a soccer ball off the ground and in the air, with an initial velocity of 35 feet per second. Using the formula H(t)
sesenic [268]

Answer:

Step-by-step explanation:

The function for this problem is: h(t) = -16(t)^2 + vt + s h= the height t= time v= velocity s= starting height With the information given, we know that the starting height is 0, since it was from the ground, and the velocity of the ball is 35 feet per second. Inserting the these information into the equation, we get: h(t) = -16(t)^2 + 35t Now the question asks to find the maximum height. It can be done by using a grapher to graph the maximum of the parabola. It could also be done by finding the vertex, which would be the maximum, of the graph by using x= -b/(2a), where b is equal to 35 and a is equal to -16. We get x=35/32, the x-value of where the vertex lies. You can use this value as the t-value in the previous equation to find the h-value of the vertex. When you do, you get h= 19.1 feet, or answer D.

hope this helps

6 0
3 years ago
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