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lions [1.4K]
3 years ago
9

Subtract

Mathematics
1 answer:
dem82 [27]3 years ago
3 0

Answer: I think its 12x+2

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Can you please show me how to do:
USPshnik [31]

Step-by-step explanation:

6\sqrt3\cdot\dfrac{\sqrt3}{3}=\dfrac{(6\sqrt3)(\sqrt3)}{3}\\\\\text{use the associative property}\ (a\times b)\times c=a\times(b\times c)\\\\=\dfrac{(6)(\sqrt3\cdot\sqrt3)}{3}\\\\\text{use}\ \sqrt{a}\cdot\sqrt{a}=a\\\\=\dfrac{(6)(\not3)}{\not3}\qquad\text{cancel 3}\\\\=6

3 0
3 years ago
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Thе іmagе оf (-2, 5) is (1, 1).
dem82 [27]

Answer:

  (6, -2)

Step-by-step explanation:

To get to x=1 from x=-2, you must add 3 to the x-coordinate. Only one answer choice has an x-coordinate that is 3 more than that of the given point:

  3 + 3 = 6

The image point is (6, -2).

_____

<em>Check</em>

To get from a y-coordinate of 5 to an image point y-coordinate of 1, you must subtract 4. If you subtract 4 from the y-coordinate of (3, 2), you get 2-4 = -2, the y-coordinate in the chosen answer above.

8 0
3 years ago
Can someone help me please
Sveta_85 [38]

Answer:

66.42degrees

Step-by-step explanation:

\cos {}^{ - 1} ( \frac{6}{15} )  = 66.42degrees

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What is the approximate volume of the cone ?
lubasha [3.4K]

Answer:1206cm

Step-by-step explanation:

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3 years ago
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Use the discriminant to predict the nature of the solutions to the equation 4x-3x²=10. Then, solve the equation.
AleksandrR [38]

Answer:

Two imaginary solutions:

x₁= \frac{2}{3} -\frac{1}{3} i\sqrt{26}

x₂ = \frac{2}{3} +\frac{1}{3} i\sqrt{26}

Step-by-step explanation:

When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.

The discriminant gives us information on how the solutions of the equations will be.

  1. <u>If the discriminant is zero</u>, the equation will have only one solution and it will be real
  2. <u>If the discriminant is greater than zero</u>, then the equation will have two solutions and they both will be real.
  3. <u>If the discriminant is less than zero,</u> then the equation will have two imaginary solutions (in the complex numbers)

So now we will work with the equation given: 4x - 3x² = 10

First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0

So:

4x - 3x² = 10

-3x² + 4x - 10 = 0 will be our equation

with this information we have that a = -3 b = 4 c = -10

And we will find the discriminant: b^{2} -4ac = 4^{2} -4(-3)(-10) = 16-120=-104

Therefore our discriminant is less than zero and we know<u> that our equation will have two solutions in the complex numbers. </u>

To proceed to solve the equation we will use the general formula

x₁= (-b+√b²-4ac)/2a

so x₁ = \frac{-4+\sqrt{-104} }{2(-3)} \\\frac{-4+\sqrt{-104} }{-6}\\\frac{-4+2\sqrt{-26} }{-6} \\\frac{-4+2i\sqrt{26} }{-6} \\\frac{2}{3} -\frac{1}{3} i\sqrt{26}

The second solution x₂ = (-b-√b²-4ac)/2a

so x₂=\frac{-4-\sqrt{-104} }{2(-3)} \\\frac{-4-\sqrt{-104} }{-6}\\\frac{-4-2\sqrt{-26} }{-6} \\\frac{-4-2i\sqrt{26} }{-6} \\\frac{2}{3} +\frac{1}{3} i\sqrt{26}

These are our two solutions in the imaginary numbers.

7 0
3 years ago
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