Draw a right triangle.


Arctangent (tan^-1) can be used to find theta.

Answer: Graph A
Step-by-step explanation:
Answer:
I think it would be B) A,B,C
Step-by-step explanation:
well A is smaller than B or C and B is smaller than C.
<span>Simplifying
8x + -6y = -20
</span><span>Solving
8x + -6y = -20
</span><span>Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right
</span><span>Add '6y' to each side of the equation.
8x + -6y + 6y = -20 + 6y
</span><span>Combine like terms: -6y + 6y = 0
8x + 0 = -20 + 6y
8x = -20 + 6y
</span>
Divide each side by '8'.
x = -2.5 + 0.75y
<span>Simplifying
x = -2.5 + 0.75y</span>
<span>x in (-oo:+oo)
(x+20)/2 = 3*x // - 3*x
(x+20)/2-(3*x) = 0
(x+20)/2-3*x = 0
(x+20)/2+(-3*2*x)/2 = 0
x-3*2*x+20 = 0
20-5*x = 0
(20-5*x)/2 = 0
(20-5*x)/2 = 0 // * 2
20-5*x = 0
20-5*x = 0 // - 20
-5*x = -20 // : -5
x = -20/(-5)
x = 4 so x= 4</span>