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2 years ago

During a semester, a student received scores of 76, 80, 83,

Mathematics

1 answer:

Fantom [35]2 years ago

5 0

Add all those numbers and divide by 6 will get you 78

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I need an Answer Immediately,pls!!!!!!

Leya [2.2K]

Answer:

See below.

Step-by-step explanation:

$41.5 + 5x = 52.5\\5x = 11\\x = 2.2$

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2 years ago

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Graph the line that passes through the points (9, -9) and (9,−4) and determine the equation of the line.

yKpoI14uk [10]

Answer:

x = 9

Step-by-step explanation:

Since both points share the same x-coordinate, look no further.

It has to be a vertical line with x-coordinate 9.

8 0

3 years ago

In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that

attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable $X\sim Poisson(\lambda = 0.62)$ .

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

= 1 - P (X = 0) - P (X = 1)

$=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252$

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: $\lambda=7\times0.62=4.34$

Compute the probability of no deaths in a corps over 7 years as follows:

$P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130$

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

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2 years ago

Can someone please help me with this

KatRina [158]

Answer:

13)5m-10

14)8y+16

15)-3m-12

16)a²+3a

17)h²-2h

18)2m²+8m

19)-2z+16

20)-4x²+40x

21) 12x and 60

22)x and 4

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2 years ago

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A carpenter has a rectangular wooden board. The diagonal of the board is 18 inches long and one side of the board is 12 inches l

BaLLatris [955]

In this question, it is given that the diagonal of the board is 18 inches long and one side of the board is 12 inches long.

Let the other side is of length b inches .

Now we use pythagorean identity, which is

$a^2 + b ^2 = c^2$

Here, a = 12 and c=18

Substituting these values, we will get

$12^2 + b^2 = 18^2 \\ 144 + b ^2 = 324 \\ b^2 = 324-144 \\ b^2 = 180 \\ b= \sqrt{180} \\ b = 13.4164 inches$

And the formula of perimeter is

$Perimeter = 2(Sum\ of \ legs)$

Substituting the values of the two legs, we will get

$Perimeter = 2(12+13.4164) = 50.83 inches$

3 0

3 years ago

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