Answer:
More advanced transformation geometry is done on the coordinate plane. The transformation for this example would be T(x, y) = (x+5, y+3). A reflection is a "flip" of an object over a line.
Answer:
The percent of the parts are expected to fail before the 2100 hours is 0.15.
Step-by-step explanation:
Given :Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 hours.
To Find : If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?.
Solution:
We will use z score formula
Mean value = 
Standard deviation = 
We are supposed to find If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?
So we are supposed to find P(z<2100)
so, x = 2100
Substitute the values in the formula
Now to find P(z<2100) we will use z table
At z = −2.96 the value is 0.0015
So, In percent = 
Hence The percent of the parts are expected to fail before the 2100 hours is 0.15.
If you would like to know how much dip remains, you can calculate this using the following steps:
1 quart = 32 ounces
<span>1 quart and 2 ounces = 32 ounces + 2 ounces = 34 ounces of vegetable dip
</span>1 cup = 8 ounces<span>3 cups = 3 * 8 ounces = 24 ounces
</span><span>3 cups and 3 ounces = 24 ounces + 3 ounces = 27 ounces poured into a bowl
</span>
remaining: 34 ounces - 27 ounces = 7 ounces
The correct result would be 7 ounces.
Answer:
The linear function would be:
C = 10t + 2
where C is the cost and t is time in months
Step-by-step explanation:
Answer:
The null hypothesis can't be rejected.
Step-by-step explanation:
Given information:
Null hypothesis:
H₀ : π ≤ 0.70
Alternative hypothesis:
H₁ : π > 0.70
We need to check whether the null hypothesis is rejected or accepted.
If P-value < α, then we reject the null hypothesis H₀.
If P-value ≥ α, then we accept the null hypothesis H₀.
A sample of 100 observations revealed that p = 0.75 at the 0.05 significance level.
Here 0.75>0.05, it means p > α, therefore we can not reject the null hypothesis.
