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seraphim [82]
3 years ago
11

Help I need this by tomorrow

Mathematics
2 answers:
vivado [14]3 years ago
8 0

Answer:

9- their sum is 90

10- every angle of a rectangle is a right angle.

when it is intersected into two angles their sum is 90

11-PKQ=NKM vertically opposite angles

alsoNKM+MKL=90

X+14+X=90 COMPLEMENTARY ANGLES

W

2X=76

X=38

PKQ=NKM=X+14=52

14- the sum of complementary angles is 90

vertically opposite angles are equal

Step-by-step explanation:

creativ13 [48]3 years ago
5 0

not very clear queation

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You would have 14.76 trees cut
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Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v
jeyben [28]

Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

<u>Step :-(i)</u>

Given  x = 1 6 (u + v)  …(i)

  Differentiating equation (i) partially with respective to 'u'

               \frac{∂x}{∂u} = 16(1)+16(0)=16

  Differentiating equation (i) partially with respective to 'v'

              \frac{∂x}{∂v} = 16(0)+16(1)=16

  Differentiating equation (i)  partially with respective to 'w'

               \frac{∂x}{∂w} = 0

Given  y = 1 6 (u − v) …(ii)

  Differentiating equation (ii) partially with respective to 'u'

               \frac{∂y}{∂u} = 16(1) - 16(0)=16

 Differentiating equation (ii) partially with respective to 'v'

               \frac{∂y}{∂v} = 16(0) - 16(1)= - 16

Differentiating equation (ii)  partially with respective to 'w'

               \frac{∂y}{∂w} = 0

Given   z = 6uvw   ..(iii)

Differentiating equation (iii) partially with respective to 'u'

               \frac{∂z}{∂u} = 6vw

Differentiating equation (iii) partially with respective to 'v'

               \frac{∂z}{∂v} =6 u (1)w=6uw

Differentiating equation (iii) partially with respective to 'w'

               \frac{∂z}{∂w} =6 uv(1)=6uv

<u>Step :-(ii)</u>

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

                                                         \left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|

   Determinant       16(-16×6uv-0)-16(16×6uv)+0(0) = - 1536uv-1536uv

                                                                                 = -3072uv

<u>Final answer</u>:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

 

               

     

6 0
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4. Describe the number set(s) the number belongs to: −√17
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-√17 belongs in only one number set: irrational.
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Answer:

25 boxes.

Step-by-step explanation:

We have the inequality:

190 + 60x ≤ 1740  where  x = the number of boxes of books.

60x  ≤  1740 - 190

60x   ≤  1550

x ≤ 25.83.

6 0
3 years ago
Read 2 more answers
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