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3 years ago

PLS HELP SOLVE! and pls show work

Mathematics

1 answer:

Maurinko [17]3 years ago

6 0

Answer:

see explanation

Step-by-step explanation:

( $\frac{g}{h}$ )(t) = $\frac{g(t)}{h(t)}$ = $\frac{t+3}{3t-4}$

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Solve - 2/5x is less than or equal to 20

sashaice [31]

Answer:

x is less than or equal to 0

Step-by-step explanation:

- you need to multiply both sides of the inequality by 5/2

- then you reduce the numbers with the greatest common factor 5

- then you reduce the numbers with the greatest common factor 2

- any expression multiplied by 0 equals 0

- so you get x is less than or equal to 0

^^^ hope this helps! :)

8 0

3 years ago

Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the

igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:

Steps

1. Calculate the mean of reported heights

Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

Mean of reported heights = 65.5

2. Calculate the mean of measured heights

Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10

Mean of measured heights = 647.5/10

Mean of measured heights = 64.75

3. Get their difference

Difference = Mean of reported heights - Mean of measured heights

Difference = 65.5 - 64.75

Difference = 0,75

Method 2: Calculate the mean of their difference

Mean of difference = Sum of difference / Number of observations

Mean of difference = (-1 + 0 + 1 + 1.5 + 3 + 0 + 2 + 1 – 0.5 + 0.5)/10

Mean of difference = 7.5/10

Mean of difference = 0.75

Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

3 0

3 years ago

Read 2 more answers

Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i

shepuryov [24]

Answer:D) 1 hr

Step-by-step explanation:

Given

Pump A and B can fill tank in $\frac{6}{5} hr$

Pump A and C can fill tank in $\frac{3}{2} hr$

Pump B and C can fill tank in $2 hr$

Let A be the total hr taken A therefore rate of $A=\frac{1}{A} /hr$

Let B be the total hr taken B therefore rate of $B=\frac{1}{B} /hr$

Let C be the total hr taken C therefore rate of $C=\frac{1}{C} /hr$

$\frac{1}{A}+\frac{1}{B}=\frac{5}{6}$ -----1

$\frac{1}{B}+\frac{1}{C}=\frac{1}{2}$ -----2

$\frac{1}{A}+\frac{1}{C}=\frac{2}{3}$ -----3

Adding 1,2 & 3

$2(\frac{1}{A}+\frac{1}{B}+\frac{1}{C})=\frac{5}{6}+\frac{1}{2}+\frac{2}{3}$

$\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{2}{2}$

$\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1$

thus time taken by A,B and C combined is 1 hr

7 0

3 years ago

5) Linda picked a basket of apples. She gave half of the apples to a neighbor, then 10 apples to her mother, then half of the re

mihalych1998 [28]

Answer:

is it 8 apples to her mother or 10 since I had this exact problem?

Step-by-step explanation:

3 0

4 years ago

Please post how you got the answer I've been having trouble with these

emmainna [20.7K]

Set up the equation it's equavilvent to the same side of the other one
x-1=6
+1=+1
x=7

7 0

3 years ago

Read 2 more answers