Answer:
45
Step-by-step explanation:
Answer: The height of the new player is 210 cm
Step-by-step explanation: The previous mean of the entire team has been calculated as 200.3
What this means is that, we have a summation of the observed data and a summation of the frequency of data.
The mean was calculated as
Sum FX/Sum F = 200.3
Where Sum FX is 2604 and Sum F is 13
However, our calculation should now read thus,
Sum FX/Sum F = 201 {where 201 is the new mean}
By cross multiplication we now have
Sum FX = Sum F x 201
Remember that a new member has joined the team so our Sum F is now 14 and we can now express it as thus
Sum FX = 14 x 201
Sum FX = 2814
If the summation of the observed data after adding a new team member is now 2814, then the addition to the previous observed data would be
2814 - 2604 = 210
So the height of the new member added to the team is 210 cm.
Answer:

Step-by-step explanation:
We know i×i=i^2 which has value of -1.
We will multiply numerator and denominator by i so the denominator will no longer contain imaginary part(s).
Also multiplying by i/i does not change the value of the fraction because i/i=1.
Numerator × i gives (-5+i)i=-5i+i^2=-5i-1
=-1-5i.
Denominator × i gives (2i)i=2i^2=-2.
So the simplified version of this fraction given is:

The last simplification come from me multiplying fraction by -1/-1.
The new pool is 18.84 feet larger in circumference than the old one.
<u>Explanation:</u>
Given:
Circumference of the pool = 47.1 feet
Diameter of the new pool, d = 21 feet
radius, r = 21/2 feet
Circumference of the new pool = ?
We know:
Circumference = 2πr
where,
r is the radius
On substituting the value:
C = 
C = 65.94 feet
The difference in circumference of the two pools = 65.94 - 47.1 feet
= 18.84 feet
Therefore, the new pool is 18.84 feet larger in circumference than the old one.