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2 years ago

PLES ANSWER FAST! I THIS IS DUE IN 5 MINUTES

Mathematics

2 answers:

babunello [35]2 years ago

7 0

Answer:

The answer is 12ac^14/b^3

artcher [175]2 years ago

4 0

Answer

12ac^14/b^3

Step-by-step explanation:

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What is 1/4 of 3/5 of customers

shepuryov [24]

The answer is 7/20. 1/4= 5/20 and 3/5 = 12/20 What I did was find the GCF (greatest common factor) of both 4 and 5 which was 20. Then I multiplied both numerators by the same number I multiplied the denominator with. Afterwards I subtracted both numerators (12-5) and this equals to 7 Hope that helps

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3 years ago

Explain how you can find the constant of proportionality from a graph representing a proportional relationship when it shows a p

Vladimir [108]

tienees que fijartelos extrreemos

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2 years ago

X/2 + 3/2 < 5/2 give solution

Nataly [62]

Start with

$\dfrac{x}{2}+\dfrac{3}{2}$

Multiply the whole equation by 2. Since 2 is positive, we don't need to switch the inequality sign:

$x+3$

Subtract 3 from both sides:

$x$

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2 years ago

Jen has 6 yards of fabric and wants to make a new dress and shorts she used 3 1/3 yards of the fabric on her new dress how much

kodGreya [7K]

Answer:

$2\frac{2}{3}\ yards$

Step-by-step explanation:

we know that

To find out how much fabric Jen has left for the shorts, subtract the yards of fabric used in her new dress from the total yards of fabric Jen has.

$6-3\frac{1}{3}$

Convert mixed number to an improper fraction

$3\frac{1}{3}=\frac{3*3+1}{3}=\frac{10}{3}$

substitute

$6-3\frac{1}{3}=6-\frac{10}{3}=\frac{8}{3}\ yards$

Convert to mixed number

$\frac{8}{3}\ yards=\frac{6}{3}+\frac{2}{3}=2\frac{2}{3}\ yards$

5 0

2 years ago

A triangular course for a canoe race is marked with buoys. The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg

balu736 [363]

<h2>The race is 1.2 miles long</h2>

Step-by-step explanation:

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

$\texttt{Length of first leg = }\frac{3}{10}miles\\\\\texttt{Length of second leg = }\frac{1}{2}miles\\\\\texttt{Length of third leg = }\frac{2}{5}miles$

Now we need to find length of race

$\texttt{Total length = }\frac{3}{10}+\frac{1}{2}+\frac{2}{5}\\\\\texttt{Total length = }\frac{3}{10}+\frac{5}{10}+\frac{4}{10}\\\\\texttt{Total length = }\frac{3+5+4}{10}\\\\\texttt{Total length = }\frac{12}{10}\\\\\texttt{Total length = }1.2miles$

The race is 1.2 miles long

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2 years ago