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puteri [66]
3 years ago
15

Two horses are ready to return to their barn after a long workout session at the track. the horses are at coordinates H(1,10) an

d Z(10,1). Their barns are located in the same building, which is at coordinates B(-3,-9). Each unit/grid on the coordinate plane represents 100 meters. Which horse is closer to the barn? Justify your answer?

Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0
The given information are the coordinates of points H, Z and B. So, the first step to do is to plot these points on a Cartesian plane as shown in the attached picture. We can deduce visually that horse Z is closer to the barns than horse H. But, to further justify the answer, we have to provide the magnitude of the distance of horses H and Z to barn B. In this approach, we use the distance formula:

d = √(x₂ - x₁)² + (y₂ - y₁)²

Use the coordinates of the two points to know their linear distances. These are represented by the red and green lines for each of the horses.

Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B  = 19.4165

Since the scale is 1 unit = 100 meters, the actual distance between horse H and barn B is 19.416*100 = 1,941.65 meters


Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B  = 16.4012

Since the scale is 1 unit = 100 meters, the actual distance between horse Z and barn B is 16.4012*100 = 1,640.12 meters

Comparing the distances: 1,941.65 meters > 1,640.12 meters. Therefore, it justifies that horse Z is nearer to the barn.

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notka56 [123]

Answer:

There is no tangent line of the given circle at (6, 0).

Step-by-step explanation:

Given equation of the circle,

x^2 + y^2 = 1

∵ equation of a circle is (x-h)^2 +(y-k)^2 = r^2,

Where, (h, k) is the center of the circle and r is the radius,

By comparing,

Center of the given circle = (0, 0),

Radius of the circle = 1 unit

Now, check whether point (6, 0) lie on the circle,

if x = 6, 6^2 + y^2 = 1

36 + y^2 = 1

y^2 = 1- 36

y= i\sqrt{35}\neq 0

i.e., (6, 0) does not lie on the circle,

Hence, there is no tangent line of the given circle at (6, 0).

3 0
3 years ago
1 1/3 x 5/8 A.3/4 B.4/5 C.5/6 D.5/8​
dmitriy555 [2]

Answer:

c.5/6

Step-by-step explanation:

1 1/3 x 5/8  = 4/3 x  5/8

first multiply both numerator and d enumerator

then we get

20/ 24

divide both numerator and  d enumerator with 4

simplify that

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5 0
3 years ago
A closed box has a square base with side length feet and height feet given that the volume of the box is 34 ft.³ express the sur
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Answer:

\dfrac{2s^3+136}{s}

Step-by-step explanation:

Let the side length of the square base =s feet

Let the height of the box = h

Given that the volume of the box = 34$ ft^3

Volume of the box =s^2h

Then:

s^2h=34$ ft^3\\$Divide both sides by s^2\\h=\dfrac{34}{s^2}

Surface Area of a Rectangular Prism =2(lb+bh+lh)

Since we have a square base, l=b=s feet

Therefore:

Surface Area of our closed box= 2(s^2+sh+sh)

S$urface Area= 2s^2+4sh\\Recall: h=\dfrac{34}{s^2}\\$Surface Area= 2s^2+4s\left(\dfrac{34}{s^2}\right)\\=2s^2+\dfrac{136}{s}\\$Surface Area in terms of length only=\dfrac{2s^3+136}{s}

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3 years ago
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Answer:

What is it steepest slope?

Step-by-step explanation:

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