The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.
In fact, if you use complex number, then a polynomial with degree n has exactly n roots.
So, in particular, a third-degree polynomial can have at most 3 roots.
In fact, in general, if the polynomial 
has solutions 
, then you can factor it as
So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as
But this is a fourth-degree polynomial.
For this case we have:
By properties of the radicals 
So:
.
Now, for power properties we have:
Thus, 
So:
in its radical form
Answer:
in its simplest form.
in its radical form
Anyone sees the problem? I can’t see it.
2015-12-14T20:17:50+00:00If you would like to know what is the value of <span>54 - 4 * a^2 + 3 * b^3 </span>when a = -2 and b = 4, you can calculate this using the following steps:
54 - 4 * a^2 + 3 * b^3 = 54 - 4 * (-2)^2 + 3 * 4^3 = 54 - 4 * 4 + 3 * 64 = 54 - 16 + 192 = 230
If you would like to know what is the value of 54 - 4 * a^2 - 3 * b^3 when a = -2 and b = 4, you can calculate this using the following steps:
54 - 4 * a^2 - 3 * b^3 = <span>54 - 4 * (-2)^2 - 3 * 4^3 = 54 - 4 * 4 - 3 * 64 = 54 - 16 - 192 = -154</span>
