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3 years ago

34.8minuse23.897.................,................

Mathematics

1 answer:

masya89 [10]3 years ago

4 0

Answer: 10.903

Step-by-step explanation: Use long subtraction to evaluate.

Hope this helps you out! ☺

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At Cassville Middle School, students can choose to study either French or Spanish. The

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3 years ago

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Which of the following is equal to the square root of the cube root of 6?

stiks02 [169]

The correct answer is: [A]: " 6 to the power of (1 over 6) " .

Explanation:

________________________

√ [(∛6)] = √ [6⁽¹/³⁾ ] = [6⁽¹/²⁾ ] ⁽¹/³⁾ = 6^ ( ⁽¹/²⁾ * ⁽¹/³⁾ ) = ???? ;

<u>Note</u>: $\frac{1}{2} *\frac{1}{3} = \frac{(1*1)}{(2*3)} = \frac{1}{6}$ ;

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→ 6^ ( ⁽¹/²⁾ * ⁽¹/³⁾ ) ;

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→ which is: Answer choice: [A]: " 6 to the power of (1 over 6) " .

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3 years ago

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Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the

VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

$\lim_{x \to 2} f(x) = 1$

$\lim_{x \to 2} g(x) = -4$

$\lim_{x \to 2} h(x) = 0$

a) Applying properties of limits

$\lim_{x \to 2} f(x) + 5g(x) = \lim_{x \to 2} f(x) + 5 \lim_{x \to 2} g(x) = 1 + 5*-4 = -19$

b) Applying properties of limits

$\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64$

c) Applying properties of limits

$\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1$

d) Applying properties of limits

$\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16$

e) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0$

f) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0$

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4 years ago

Simplify x0 y-3/x2 y-1

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Answer:

x^0 y^-3 / x^2 y^-1

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= 1/(x^2 y^2)

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