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adell [148]
3 years ago
11

34.8minuse23.897.................,................

Mathematics
1 answer:
masya89 [10]3 years ago
4 0

Answer: 10.903

Step-by-step explanation: Use long subtraction to evaluate.

Hope this helps you out! ☺

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At Cassville Middle School, students can choose to study either French or Spanish. The
natulia [17]

Answer:

is french which is higher median number of learners

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3 years ago
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Which of the following is equal to the square root of the cube root of 6?
stiks02 [169]

The correct answer is: [A]: " 6 to the power of (1 over 6) " .

Explanation:

________________________

√ [(∛6)] = √ [6⁽¹/³⁾ ] = [6⁽¹/²⁾ ] ⁽¹/³⁾ = 6^ ( ⁽¹/²⁾ * ⁽¹/³⁾ ) = ???? ;


<u>Note</u>: \frac{1}{2}  *\frac{1}{3}      =   \frac{(1*1)}{(2*3)}    =   \frac{1}{6} ;

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→ 6^ ( ⁽¹/²⁾ * ⁽¹/³⁾ ) ;

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→ which is: Answer choice: [A]: " 6 to the power of (1 over 6) " .

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7 0
3 years ago
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Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the
VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

\lim_{x \to 2} f(x) = 1

\lim_{x \to 2} g(x) = -4

\lim_{x \to 2} h(x) = 0

a) Applying properties of limits

\lim_{x \to 2} f(x) + 5g(x) =  \lim_{x \to 2} f(x) + 5  \lim_{x \to 2} g(x) = 1 + 5*-4 = -19

b) Applying properties of limits

\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64

c) Applying properties of limits

\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1

d) Applying properties of limits

\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16

e) Applying properties of limits

\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0

f) Applying properties of limits

\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0

3 0
4 years ago
Simplify x0 y-3/x2 y-1
Natali5045456 [20]

Answer:

x^0 y^-3 / x^2 y^-1  

= 1 /  x^2 y^-1 (y^3)  ...because  x^0 = 1 and  [(y^-1) (y^3)] = y^2

= 1/(x^2 y^2)



6 0
4 years ago
Help please I don’t understand
dmitriy555 [2]
88cm^2. area is the coverage of the area inside of a given shape, since some of the frame is cut off for a picture (making it not a full rectangle) you must find the area of the whole frame and find the area of the cutout. after finding those, subtract the cutout from the frame and then you have the area of the frame
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