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3 years ago

Need help with this!!! 8 points!!!

Mathematics

1 answer:

pashok25 [27]3 years ago

6 0

Answer:

The answers is 369 and 577... good luck. ♥️♥️♥️

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Part b c and d please help

ioda

Answer:

b) Y =5.73X +4.36

C) =5.73225*(21)X +4.359

124.73625

D) 163.728 = 5.73X +4.36

X = (163.728 - 4.36)/5.73

X = 27.81291449

Year would be 2027

Step-by-step explanation:

x1 y1 x2 y2

4 27.288 16 96.075

(Y2-Y1) (96.075)-(27.288)= 68.787 ΔY 68.787

(X2-X1) (16)-(4)= 12 ΔX 12

slope= 5 41/56

B= 4 14/39

Y =5.73X +4.36

5 0

3 years ago

A particular country's exports of goods are increasing exponentially. The value of the exports, t years after 2008, can be ap

Alex_Xolod [135]

Answer:

a) For 2008 we have that t = 2008-2008 = 0 and we have:

$V(0)= 1.4e^{0.039*0}= 1.4$

For 2022 we have that t = 2022-2008=14 and if we replace we got:

$V(12) = 1.4 e^{0.039*14}=2.417$

b) $2.8 = 1.4 e^{0.039 t}$

We can divide both sides by 1.4 and we got:

$2 = e^{0.039 t}$

Now natural log on both sides:

$ln (2) = 0.039 t$

$t = \frac{ln(2)}{0.039}= 17.77 years$

Step-by-step explanation:

For this case we have the following model given:

$V(t) = 1.4 e^{0.039 t}$

Where V represent the exports of goods and the the number of years after 2008.

Part a

Estimate the value of the country's exports in 2008 and 2022

For 2008 we have that t = 2008-2008 = 0 and we have:

$V(0)= 1.4e^{0.039*0}= 1.4$

For 2022 we have that t = 2022-2008=14 and if we replace we got:

$V(12) = 1.4 e^{0.039*14}=2.417$

Part b

What is the doubling time for the value of the country's exports.

For this case we can set up the following condition:

$2.8 = 1.4 e^{0.039 t}$

We can divide both sides by 1.4 and we got:

$2 = e^{0.039 t}$

Now natural log on both sides:

$ln (2) = 0.039 t$

$t = \frac{ln(2)}{0.039}= 17.77 years$

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valina [46]

Answer: -4x

Step-by-step explanation:

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