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The probability of the offspring of a heterozygous father and homzygous mother having five fingers is 50%.
<h3>How to calculate genotype of a cross?</h3>
According to this question, a gene coding for the number of fingers in humans is involved. The allele for six fingers (F) is the dominant trait while the allele for five fingers (f) is the recessive trait.
If a cross between a heterozygous father that posseses a genotype of Ff and a homzygous mother that posseses a genotype of ff, the following offsprings will be produced:
This shows that the probability of the offspring of a heterozygous father and homzygous mother having five fingers is ½ (50%).
Learn more about genotype at: brainly.com/question/12116830
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Answer:
Explanation:
What Mendel wanted to happen was to obtain middle-sized plants. What actually happened was that Mendel got tall plants. Due to this result, Mendel called Reccesive to the genes thatdetermined the short offspring, and Dominant to the genes that determined the tall offspring.
Parents give half of their genes to their offspring that is why their offspring has some features from their dad and some from their mom
