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torisob [31]
3 years ago
9

A company plans to assign identification numbers to its employees. Each number is to consist of four different digits from 0 to

9, inclusive, except that the first digit cannot be 0. How many different identification numbers are possible?
(A) 3,024
(B) 4,536
(C) 5,040
(D) 9,000
(E) 10,000
Mathematics
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer: B) 4536

Step-by-step explanation:

Given : A company plans to assign identification numbers to its employees. Each number is to consist of four different digits from 0 to 9, inclusive, except that the first digit cannot be 0.

i.e. The number of choices for first digit = 9   (Total digits = 1)

The number of choices for second digit = 9  (one get fixed in first place and 0 can be used)

Similarly, The number of choices for third digit = 8  ( two got fixed on 1st and second place)

The number of choices for fourth digit = 7  (Three places are fixed.)

By Fundamental counting principle ,

The number of different identification numbers are possible = 9\times9\times8\times7=4536

The number of different identification numbers are possible is 4536.

Therefore , the correct answer is (B) 4,536.

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Answer:

11.6km/h

Step-by-step explanation:

multiply 30 min by 2 to get to an hour

multiply 5.8 by 2 to get to km per hour

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A summer camp has 32 campers. 22 of them swim, 20 play softball, and 5 do not play softball or swim. which values correctly comp
Lapatulllka [165]

The values which completes the table regarding summer camp is option b which is a=15,b=7, c=5, d=10, e=12.

Given that there are 32 campers, 22 of them can swim, 20 play softball and 5 do not play softball or swim.

We have to find the values of a,b,c,d,e so that we can complete the table.

Table is a combination of rows and columns. In our case the third row and third column shows the total.

from the table we can write that 22+d=32-----------1

so d=32-22

=10

d=10

c+5=d-----------2

c=10-5=5

c=5

a+c=20------------------3

a+5=20

a=20-5

a=15

a+b=22--------------3

15+b=22

b=7

20+e=32----------4

e=32-22

e=10.

Hence the values which completes the table is a=15,b=7, c=5, d=10,  e=12.

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Question is incomplete as it should include figure showing table of values.

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How far will a jet travel in 2 hours and 30 minutes if its average speed is 450 miles per hour?
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The cost of producing x units of a product is $1.25 per unit plus $1,000 in flat production costs. If you spend $3,000 on produc
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Y''+y'+y=0, y(0)=1, y'(0)=0
mars1129 [50]

Answer:

y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form ay''+by'+cy=0.

Given: y''+y'+y=0

Let y=e^{rt} be it's solution.

We get,

\left ( r^2+r+1 \right )e^{rt}=0

Since e^{rt}\neq 0, r^2+r+1=0

{ we know that for equation ax^2+bx+c=0, roots are of form x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} }

We get,

y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}

For two complex roots r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta, the general solution is of form y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )

i.e y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

Applying conditions y(0)=1 on e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right ), c_1=1

So, equation becomes y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

On differentiating with respect to t, we get

y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )

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Therefore,

y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

3 0
3 years ago
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