52.85 - 9.09 rounded to the nearest one is 44
3. | -9 | = 9
7. - | -5 * -7 | = - | 35 | = -35
15. | m + 3 | = 7
m + 3 = 7 -(m + 3) = 7
m = 7 - 3 -m - 3 = 7
m = 4 -m = 10
m = -10
so m = 4 and m = -10
17. | -3d | = 15
-3d = 15 -(-3d) = 15
d = 15/-3 3d = 15
d = - 5 d = 15/3
d = 5
so d = 5 and d = -5
19. | 4b - 5 | = 19
4b - 5 = 19 -(4b - 5) = 19
4b = 19 + 5 -4b + 5 = 19
4b = 24 -4b = 14
b = 24/4 b = 14/-4
b = 6 b = - 7/2
so b = 6 or b = -7/2
20. | x - 1 | + 5 = 2
| x - 1 | = 2 - 5
| x - 1 | = -3
There is no solution on this one because an absolute value cannot equal a negative number
21. -4 | 8 - 5n | = 13
| 8 - 5n | = - 13/4
There is also no solution for this one because of the same reason...absolute values cannot equal negative numbers
Easy!
Wouldn’t it just be
(With your formula of volume/rate=time)
250mL/2 hours=
125mL a hour
2.083(three is repeated)mL a minute
0.03472(two is repeated)mL a second
At least that’s what I think
Answer:
The dependent variable for this experiment is the ability of students with similar intellectual abilities to recall the meaning of a symbol in a textbook one week after the start of the experiment which depends on the presence or absence of noise outside the classroom.
Step-by-step explanation:
In an experiment, the independent variable is the one whose value, form or outcome is not determined by any other variable in the experiment.
The dependent variable is the one whose value, form or outcome is determined by one or more other variable(s) in the experiment.
This experiment tests the abilities of students with similar intellectual abilities to recall the meaning of a symbol in a textbook one week after the start of the experiment.
This ability was made to depend on whether there was noise or no noise outside their classrooms.
Since, this variable to be measured is determined by another variable in the experiment, it is evident that this is the dependent variable for this experiment.
Hope this Helps!!!
12,000 pounds, 1 ton = 2000 pounds
