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suter [353]
3 years ago
9

Factor the quadratic equations W^2-W-12

Mathematics
1 answer:
Alexandra [31]3 years ago
6 0
Given
W^2-W-12  =  w^2+bW+c
b=-1,
c=-12
We look for m, n so that  m+n=b=-1, m*n=c=-12, where m,n are integer factors of -12.

Now enumerate all possibilities for m*n=12
m   n  m*n   m+n
1 -12   -12    -11
2  -6    -12    -4
3  -4     -12    -1  ....... so m*n=-12, m+n=-1
The factorization is then
W^2-W-12=(W+3)(W-4)

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