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suter [353]
3 years ago
9

Factor the quadratic equations W^2-W-12

Mathematics
1 answer:
Alexandra [31]3 years ago
6 0
Given
W^2-W-12  =  w^2+bW+c
b=-1,
c=-12
We look for m, n so that  m+n=b=-1, m*n=c=-12, where m,n are integer factors of -12.

Now enumerate all possibilities for m*n=12
m   n  m*n   m+n
1 -12   -12    -11
2  -6    -12    -4
3  -4     -12    -1  ....... so m*n=-12, m+n=-1
The factorization is then
W^2-W-12=(W+3)(W-4)

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X²=14x-45 step by step please
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Answer:

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Step-by-step explanation:

So you want to get one side to equal zero so you can factor and find x. I recommend subtracting 14x and adding 45 to both sides so you don't have to deal with a negative quadratic.

X^2 - 14X +45 = 0

Now you can factor. Your looking for two factors that equal 45 and add to -14

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So out of those combinations -5 and -9 both multiply to 45 and add up to -14 so these are our common factors

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Gabriel uses 0.4 gallon of gasoline each hour mowing lawns. How much gas does he use in 4.2 hours
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Answer:

15 people

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Answer:

She gained 5 points in overall

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Shana lost points for each wrong question = 2

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Hence the total number of points gained by her is 5 points

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