If your just figuring out how much the car depreciated just by driving off the lot new...1st year.
$30,000×.30=$9,000
$30,000- $9,000=$21,000.
just take the brand new value of the car multiplied by the .30% of the 1st depreciation...take that answer ($9,000) and subtract it from your orginal value of $31,000.
which gives you $21,000
Answer:
Step-by-step explanation:
<u>Given Second-Order Homogenous Differential Equation</u>
<u>Use Auxiliary Equation</u>
<u />
<u>General Solution</u>
<u />
Note that the DE has two distinct complex solutions 
where 
and 
are arbitrary constants.
Answer:
y = 11
Step-by-step explanation:
8 × 2 + 5²- y = 2(y + 1) + 6
8 × 2 + 5²- y = 2y + 2 + 6
8 × 2 + 25 - y = 2y + 2 + 6
16 + 25 - y = 2y + 2 + 6
41 - y = 2y + 8
41 (- y + y) = (2y + y) + 8
41 = 3y + 8
41 - 8 = 3y (+ 8 - 8)
33 = 3y
33/3 = 3y/3
y = 11
Answer:
your and is b.
Step-by-step explanation:
mass(m)=4,500
volume(v)=0.5m³
now,
density=<u>m</u>
v
=<u>4</u><u>5</u><u>0</u><u>0</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>0.5
=9000kg/m³
12miles per hour=1hr
1sec=12÷3600=0.00333333
