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Gnesinka [82]
3 years ago
6

Please help me I am clueless

Mathematics
1 answer:
Anastaziya [24]3 years ago
7 0
The first one on the right

If b is greater, then it will be to the right of a
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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)
vagabundo [1.1K]

Answer:

Considering the given equation y = log_{3}x\\

And the ordered pairs in the format (x, y)

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For (\frac{1}{3}, a_{0} )

x=\frac{1}{3}

y=a_{0}

y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1

So the ordered pair will be (\frac{1}{3}, -1 )

For (1, a_{1} )

x=1

y=a_{1}

y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0

So the ordered pair will be (1, 0 )

For (3, a_{2} )

x=3

y=a_{2}

y = log_{3}x\\y = log_{3}3\\y = 1

So the ordered pair will be (3, 1 )

For (9, a_{3} )

x=9

y=a_{3}

y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2

So the ordered pair will be (9, 2 )

For (27, a_{4} )

x=27

y=a_{4}

y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3

So the ordered pair will be (27, 3 )

For (81, a_{5} )

x=81

y=a_{5}

y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4

So the ordered pair will be (81, 4 )

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The product of -2 and a number x is greater than 30 Write the word sentence as a inequality, then solve inequality, thank you!
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-2x > 30 

x > -15 (??)
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3 years ago
Help me once more please
Damm [24]
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A washer has outer radius 2-x^2 and inner radius 2 - \sqrt{x}

\displaystyle V = \int_0^1 \pi\Big[ \left( 2 - x^2 \right)^2 - \left( 2 - \sqrt{x}\right)^2\Big] dx

4 0
3 years ago
Convert 110 km/myr (kilometers per million years) to cm/yr (centimeters per year)
jenyasd209 [6]

Answer:

110\ \text{km/myr} =11\ \text{cm/yr}

Step-by-step explanation:

To find : Convert 110 km/myr (kilometers per million years) to cm/yr (centimeters per year) ?

Solution :

Using metric conversions,

1 kilometer = 1000 meter

1 meter = 100 centimeter

So, 1 kilometer = 100,000 centimeter

and 1 million year = 1,000,000 year

1\ \text{km/myr} =\frac{100000}{1000000}\ \text{cm/yr}

1\ \text{km/myr} =0.1\ \text{cm/yr}

So, 110\ \text{km/myr} =110\times 0.1\ \text{cm/yr}

110\ \text{km/myr} =11\ \text{cm/yr}

Therefore, 110\ \text{km/myr} =11\ \text{cm/yr}

6 0
3 years ago
Read 2 more answers
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