Question

Fred walks toward Jon's house at 4 mi/h. Jon leaves his house at the same time and walks towards Fred's house on the same path at a rate of 2 mi/h. How long will it take before they meet if the distance is 6 miles?

Answer 1

Answer:it will take 1 hour before they meet.

Step-by-step explanation:

The distance between Fred's house and Jon's house is 6 miles. This means that by the time they meet, both of them would have covered a total distance of 6 miles.

Let t represent the time spent by Fred in covering his own distance and also the time spent by Jon in covering his own distance since they left their houses at the same time.

Distance = speed × time

Distance covered by Fred would be

4 × t = 4t

Distance covered by Jon would be

2 × t = 2t

Since total distance = 6 miles, then

4t + 2t = 6

6t = 6

t = 6/6 = 1