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3 years ago

Which term describes a function in which there is a common difference

Mathematics

1 answer:

saul85 [17]3 years ago

7 0

i think it might be linear function

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Please help 25 points and brainliest

-BARSIC- [3]

Answer:

1a. 8

1b. AB & BC

1c. AC

2. $\sqrt{52}$ miles

3. NO

Step-by-step explanation:

1a. AC is your hypotenuse which is C² and BC is B², so we plug it in the equation.

A²+6²=10²

A²+36=100

A²=64

A= $\sqrt{64}$

A=8

1b. Legs are the two shorter sides, AB & BC, which are 6 & 8 respectively.

1c. The hypotenuse is the longest side AC

2. Make lines that make the graph for a triangle with a line. My graph is linked below. Then counts the points, AC=6, BC=4, then use the pythagorean therom.

6²+4²=X²

36+16=52

$\sqrt{52}$ =X

3. 15²+17²=19²

514=361

not possible

so it is not a right triangle

7 0

3 years ago

Pls help me out ! i’ll mark you brainliest

Vlad [161]

If s=2, then t= 2(2)-3 = 1
T=2(4)-3= 5
T=2(6)-3= 9
T=2(8)-3=13

6 0

3 years ago

Read 2 more answers

The width of a rectangle measures (3c-9d)(3c−9d) centimeters, and its length measures (8c-2d)(8c−2d) centimeters. Which expressi

Vsevolod [243]

The expression for the perimeter of the rectangle is 2(11c - 11d)

Perimeter of a rectangle = 2(length + width)

Length = 3c - 9d

Length = 3c - 9d Width = 8c - 2d

The expression for the perimeter can be expressed thus :

2(3c - 9d + 8c - 2d)

Collect like terms :

2(3c + 8c - 9d - 2d)

2(11c - 11d)

Hence, the expression for the perimeter of the rectangle is 2(11c - 11d)

Learn more : brainly.com/question/2142493?referrer=searchResults

3 0

3 years ago

Read 2 more answers

Which is the equation of a hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0)?

maksim [4K]

The required equation of the hyperbola is expressed as

$\frac{x^2}{10}- \frac{y^2}{15}=1 \\$

The standard form for calculating the equation of a parabola along the x-axis is expressed as:

$\frac{(x-k)^2}{a^2}-\frac{(y-h)^2}{b^2} = 1 \ ............. 1$ where:

(h, k) is the center

(k±c, h) are the foci

$x=h\pm\frac{a^2}{c}$ is the directrix

From the question given, we can see that foci = (±5, 0)

k±c, h = ±5, 0

k = 0

h = 0

c = 5

From the directrix,

$x=h\pm\frac{a^2}{c}\\x =0\pm\frac{a^2}{5}\\\pm2 = \pm\frac{a^2}{5}\\a^2 = 10\\$

Also, we need to know that;

a²+b² = c²

10 + b² = 5²

b² = 25 - 10

b² = 15

Substituting the gotten values into the equation of a hyperbola;

$\frac{(x-0)^2}{10}- \frac{(y-0)^2}{15} =1\\\frac{x^2}{10}- \frac{y^2}{15} =1\\$

This gives the required equation of the hyperbola

Learn more on the equation of hyperbola here: brainly.com/question/20409089

4 0

3 years ago

Stretch y=5x vertically about the fixed x-axis by a factor of 2

PSYCHO15rus [73]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see

A = 2, then

y= 2(5)x ---> y = 10x

3 0

3 years ago