Okay. All we have to do is divide the price by 6, because 6 people are putting in money to help pay off the total price. So 61.56/6= 10.26. Each person would would pay $10.26 to help cover the total dinner cost.
Answer:
a x sqrt(7) - 49sqrt(x)
Step-by-step explanation:
sqrt(7x) [ sqrt(x) - 7sqrt(7)]
Distribute
sqrt(7x) *sqrt(x) - sqrt(7x)*7sqrt(7)
We know that sqrt(a) sqrt(b)= sqrt(ab)
sqrt(7x^2) - 7sqrt(7^2 *x)
Now lets separate out the perfect squares
sqrt(7) *sqrt(x^2) - 7sqrt(7^2)*sqrt(x)
x sqrt(7) - 7*7sqrt(x)
x sqrt(7) - 49sqrt(x)
We know the length and width. We're just trying to find all of the area in between. To find area, we do length*width. Length is 11.5 and the width is 10.75. 11.5*10.75=123.625 ft^2
To find the midpoint, Add the two X coordinates together then divde by two and then to the same with the Y coordinates:
X = -4 + 2 = -2 / 2 = -1
Y = 6+7 = 13/2
Midpoint = (-1,13/2)
vi is going in the positive direction (up). (That's my choice). a (acceleration) is going in the minus direction (down). The directions could be reversed.
Givens
vi = 160 ft/s
vf = 0 (the rocket stops at the maximum height.)
a = - 9.81 m/s
t = ????
Remark
YOu have 4 parameters between the givens and what you want to solve. Only 1 equation will relate those 4. Always always list your givens with these problems so you can pick the right equation.
Equation
a = (vf - vi)/t
Solve
- 32 = (0 - 160)/t Multiply both sides by t
-32 * t = - 160 Divide by -32
t = - 160/-32
t = 5
You will also need to solve for the height to answer part B
t = 5
vi = 160 m/s
a = - 32
d = ???
d = vi*t + 1/2 a t^2
d = 160*5 + 1/2 * - 32 * 5^2
d = 800 - 400
d = 400 feet
Part B
You are at the maximum height. vi is 0 this time because you are starting to descend.
vi = 0
a = 32 m/s^2
d = 400 feet
t = ??
formula
d = vi*t + 1/2 a t^2
400 = 0 + 1/2 * 32 * t^2
400 = 16 * t^2
400/16 = t^2
t^2 = 25
t = 5 sec
The free fall takes the same amount of time to come down as it did to go up. Sort of an amazing result.
