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Nana76 [90]
3 years ago
5

35/16as decimal to the nearest hundredth

Mathematics
1 answer:
madreJ [45]3 years ago
5 0
35/16 is equal to 2.18
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I really need this ASAP! what is 14 2/7 as a fraction
nlexa [21]
Multiply 14 by the denominator of the fraction.

14 • 7 = 98

Then add it to the numerator.

98 + 2 = 100

Your answer is 100/7
8 0
3 years ago
Vani bought two pounds of strawberries for $8.00. What is the price, in dollars per ounce of strawberries?
WARRIOR [948]

Answer:

the prize is 8.00 for 1 pound

7 0
2 years ago
What single percentage change is equivalent to a 15% increase followed by a 16% increase?​
FromTheMoon [43]

Answer:

15% increased

=16% increased

=17% invreased

Step-by-step explanation:

8 0
2 years ago
A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.
oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

H_0: \mu=2.4\\\\H_a:\mu> 2.4

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58

The degrees of freedom for this sample size are:

df=n-1=45-1=44

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>2.5801)=0.0066

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0
3 years ago
Giving braileist for answer
Margaret [11]

Answer:

a is the answer

Step-by-step explanation:

a is the answer because the way they are being multiplied are consistent, while the others arent.

4 0
2 years ago
Read 2 more answers
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