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Roman55 [17]
4 years ago
11

12.03,1.2,12.3,1.203,12.301 order least to greatest

Mathematics
1 answer:
m_a_m_a [10]4 years ago
8 0

Answer:

1,2, 1,203, 12,03, 12,3, 12,301

Step-by-step explanation:

1,2 → 1,200

1,203

12,3 → 12,300

12,301

I am joyous to assist you anytime.

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ArbitrLikvidat [17]

Answer:

a: 24km

b: 4.8 in

Step-by-step explanation:

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4 years ago
I will give BRAINLIEST to whoever is CORRECT
Leto [7]
If i’m understanding this correctly it is BQ- CV
6 0
3 years ago
Please help! • all numbered streets runs parallel to each other. both 3rd and 4th streets are intersected by King Ave. as shown
MA_775_DIABLO [31]

(a) m∠a = 100°

(b) m∠b = 80°

(c) m∠c = 100°

Solution:

Given 3rd and 4th street are parallel lines and King Ave is a transveral line.

<em>Sum of the adjacent angles in a straight line = 180°</em>

⇒ m∠a + 80° = 180°

⇒ m∠a = 180° – 80°

⇒ m∠a = 100°

∠c and ∠a are vertically opposite angles.

<em>If two lines are intersecting, then the vertically opposite angles are congruent.</em>

⇒ ∠c ≅ ∠a

⇒ m∠c = m∠a

⇒ m∠c = 100°

<em>If two parallel lines are cut by a transversal, then the corresponding angles in the same side of the transversal are congruent.</em>

80° and angle b are corresponding angles.

⇒ m∠b = 80°

Hence m∠a = 100°, m∠b = 80° and m∠c = 100°.

8 0
4 years ago
A membership committee of three is formed from four eligible members. let the eligible members be represented by a, b, c, and d.
Lynna [10]

The correct statements are:

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1)

There are four ways to choose the committee.

This statement is true.

since we have to choose 3 members out of the 4 members so we can use the method of combination.

2)

There are three ways to form the committee if person D must be on it.

This statement is also true.

since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3)

If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

i.e. there are 35 combinations possible.

4)

If persons B and C must be on the committee, there are two ways to form the committee.

if B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5)

If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be in the committee then as in last option we have to choose any one of the two person left.

so possible number of ways are 2.

Hence, the statement is false.

Learn more about Combinations:

brainly.com/question/4658834

#SPJ4

3 0
3 years ago
Angel has 5 cakes. he wants to cut them into 1/5 pieces. how many pieces will he be able to cut?
natima [27]

Answer:

25

Step-by-step explanation:

5*5=25

5 0
3 years ago
Read 2 more answers
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