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Alika [10]
3 years ago
14

F(9) if f(x) = x + 13​

Mathematics
1 answer:
Firlakuza [10]3 years ago
3 0

Answer:

x=(-4)

Step-by-step explanation:

You simply replace f(x) with f(9)

9 = x+13

(-4)=x

x=(-4)

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What is nine plus 12
lbvjy [14]

Answer:

21

Step-by-step explanation:

4 0
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Dalia saved $3000 last year. She said $600 in the month of January. What percent of the total amount of money she saved last yea
Anni [7]
1. We assume, that the number 3000 is 100% - because it's the output value of the task. 
<span>2. We assume, that x is the value we are looking for. </span>
<span>3. If 100% equals 3000, so we can write it down as 100%=3000. </span>
<span>4. We know, that x% equals 600 of the output value, so we can write it down as x%=600. </span>
5. Now we have two simple equations:
1) 100%=3000
2) x%=600
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
100%/x%=3000/600
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for 600 is what percent of 3000

100%/x%=3000/600
<span>(100/x)*x=(3000/600)*x       - </span>we multiply both sides of the equation by x
<span>100=5*x       - </span>we divide both sides of the equation by (5) to get x
<span>100/5=x </span>
<span>20=x </span>
<span>x=20
So 600 is 20% of 3000</span>
7 0
4 years ago
Anyone know what 422,391÷28=<br>​
saul85 [17]
15085.3929
Explanation
Use a calculator
5 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!
Ludmilka [50]

Answer:

<h2>The population will reach 1200 after about 2.8 years</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

The population of a certain species of bird in a region after t years can be modeled by the function P(t) = 1620/ 1+1.15e-0.42t , where t ≥ 0. When will the population reach 1,200?

According to question we are to calculate the time t that the population P(t) will reach 1200.To do this we will substitute P(t) = 1,200 into the equation and calculate for the time 't'.

Given;

P(t) = \frac{1620}{1+1.15e^{-0.42t} } \\\\at \ P(t)= 1200;\\\\1200 =  \frac{1620}{1+1.15e^{-0.42t} }\\\\cross\ multiplying\\\\1+1.15e^{-0.42t} = \frac{1620}{1200} \\\\1+1.15e^{-0.42t}  = 1.35\\\\1.15e^{-0.42t} = 1.35-1\\\\e^{-0.42t} = \frac{0.35}{1.15}\\ \\e^{-0.42t}  = 0.3043\\\\Taking \ ln\ of\ both\ sides\\\\lne^{-0.42t}  = ln0.3043\\\\-0.42t = -1.1897\\\\t = \frac{-1.1897}{-0.42} \\\\t = 2.8 years\\\\

The population will reach 1200 after about 2.8 years

6 0
3 years ago
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