AD = DB
Angle ADE = Angle CDB
Angle DAE = Angle DBC (Alternate angles)
Angle DEA = Angle DCB (Alternate angles)
Since you have two congruent angles and one congruent side, triangle ADE is congruent to triangle CDB. This means that DE is congruent to DC implying D is the midpoint of CE.
7x - 44 = 4x + 4
Add both sides 44
7x - 44 + 44 = 4x + 4 + 44
7x = 4x + 48
Subtract both sides 4x
7x - 4x = 4x - 4x + 48
3x = 48
Divide both sides by 3
3x ÷ 3 = 48 ÷ 3
<h2>x = 16 </h2>
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Suppose that the angle between 39 and 4x + 4 is t degrees as you know they make a straight line together thus :
39 + t + 4x + 4 = 180
39 + t + 4(16) + 4 = 180
39 + t + 64 + 4 = 180
39 + t + 68 = 180
t + 107 = 180
Subtract both sides 107
t + 107 - 107 = 180 - 107
<h2>t = 73 </h2>
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8y - 43 = 4x + 4 + t
8y - 43 = 4(16) + 4 + 73
8y - 43 = 64 + 4 + 73
8y - 43 = 68 + 73
8y - 43 = 141
Add both sides 43
8y - 43 + 43 = 141 + 43
8y = 184
Divide both sides by 8
8y ÷ 8 = 184 ÷ 8
<h2>y = 23 </h2>
It would still be a circle
Remember you can do anything to an equaiton as long asyou do it to both sides
4v+18≥6v+10
minus 4v both sides
4v-4v+18≥6v-4v+10
0+18≥2v+10
18≥2v+10
minus 10 both sides
18-10≥2v+10-10
8≥2v+0
8≥2v
divide both sides by 2
8/2=(2v)/2
4≥(2/2)v
4≥1v
4≥v
v≤4
Answer:
I hope this helps
Step-by-step explanation:
The answer is 5454
