The complete question is
A fence must be built to enclose a rectangular area of 5000ft^2. Fencing material costs $1 per foot for the two sides facing north and south and 2$ per foot for the other two sides. Find the cost of the least expensive fence.
Answer:
Total cost will be $400
Step-by-step explanation:
Let x = be other side
y = north and south side
Area = x*y = 5000
Perimeter of the rectangle = 2x + 2y
cost of fencing = 2(1)*5000/x + 2*2x
= 10000/x + 4x
now to get the least we will take the derivative of this
C'(x) = 10000(-1/x^2) + 4 =0
x^2 = 2500
x= 50ft cost = 2*$2*50 = $200
y= 100ft cost = 2*$1*100 = $200
Total cost = $400
6/ sqrt(8)=
6/sqrt(8) * sqrt(8)/sqrt(8)
6sqrt(8)/8
3/4 * sqrt(8)
3/4 * sqrt(4*2)
3/4 * sqrt(4) * sqrt(2)
3/4 *2*sqrt(2)
3/2 *sqrt(2)
5/sqrt(11) *sqrt(11)/sqrt(11)
5sqrt(11)/11
5/11 *sqrt(11)
2.4*x/2=34.68
2.4*x=69.36
x=28.9
(x is the height)
Answer:
Option 4
Step-by-step explanation:
Trying the first 2 pairs and confirm the Last Option
y=5*2^x
I think the answers would be
four outcomes (bc four colors)
and
a 36% chance of grabbing a blue marble (4blue/11total)
