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4 years ago

- 2X +3Y=7 5x+8y=-2 Solution=(_,_)

Mathematics

1 answer:

Leya [2.2K]4 years ago

3 0

Answer:

The solution is the point (-2,1)

Step-by-step explanation:

we have

$-2x+3y=7$ ----> equation A

$5x+8y=-2$ ----> equation B

Solve the system of equations by graphing

Remember that the solution of the system is the intersection point both lines

using a graphing tool

The solution is the point (-2,1)

see the attached figure

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Maria has $46 to buy fish for her aquarium. Each goldfish costs $6. How

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Let's set it up like this:
$\frac{\frac{x}{3}-\frac{y}{4}}{\frac{x}{4}+\frac{y}{3}}$
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4 years ago

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Please help. ive been up all morning trying to get all my late work turned in anyone. please help

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Answer:

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3 years ago

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Explain why it would not make sense to approximate 256 using the binomial theorem for the binomial (20 + 5)6.

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The formula for the Binomial Theorem with a power 6 is as:

$(x+y)^6=x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6$

Thus, if we plug in 20 for x and 5 for y, our first term itself will be $20^6=64000000$ which is much greater than 256 and thus it will not make any sense to use $(20+5)^6$ to approximate 256 using the binomial theorem.

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Our best bet here would be to use the equation with power 8:

$(x+y)^8=x^8+8x^7y+28x^6y^2+56x^5y^3+70x^4y^4+56x^3y^8+28x^2y^6+7xy^7+y^8$

and have $x=1$ and $y=1$ which will give us

$(1+1)^8=1^8+8(1)^7(1)+28(1)^6(1)^2+56(1)^5(1)^3+70(1)^4(1)^4+56(1)^3(1)^8+28(1)^2(1)^6+7(1)(1)^7+(1)^8 =256$

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