What is the solution to the system of equations? 3x + 10y = -47 5x- 7y = 40Please and thank u
2 answers:
Answer: x=1; y=-5
Step-by-step explanation: To solve this system we can use differente methods, in this case we are going to use substitution:
first equation: 3x+10y=-47
second equation: 5x-7y=40
we are going to isolate x from the first equation:
3x=-47-10y

now we replace it in the second equation:

and now we solve for y:






y=-5
now we replace the value of y in the first equation and solve for x:




x=1
Answer:
x=1, y=-5
Step-by-step explanation:
Given equations are:

In order to solve the equation
Multiplying Eqn 1 by 5 and eqn 2 by 3 and subtracting them
So,
Eqn 1 becomes
15x+50y=-235
Eqn 2 becomes
15x-21y=120
Subtracting 2 from a
15x+50y - (15x-21y) = -235-120
15x+50y-15x + 21y = -355
71y = -355
y = -355/71
y =-5
Putting y= -5 in eqn 1
3x+10(-5) = -47
3x -50 = -47
3x = -47+50
3x = 3
x = 3/3
x = 1
Hence the solution is:
x=1, y=-5
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