Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Do you want square root? And If so then here is the answer:Rewrite <span><span>√37</span>37</span> as <span><span>√3√7</span>37</span>.<span><span>√3√7</span>37</span>Multiply <span><span>√3√7</span>37</span> by <span><span>√7√7</span>77</span>.<span><span><span>√3√7</span><span>√7√7</span></span><span>3777</span></span>Simplify. And in the end of, this I put the decimals.√<span><span>217</span><span>217</span></span>The result can be shown in both exact and decimal forms.Exact Form:<span><span><span>√21</span>7</span></span>Decimal Form:<span>0.65465367<span>… not sure this answer.
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Answer:
#3
Step-by-step explanation:
