Answer:
Step-by-step explanation:
Given
Solving (a): n
To solve for n;
We make use of
Substitute values for XY and XZ
Divide through by -6
Solving (b) XY
Substitute 3 for n
Solving (c): XZ
C) and E) because for X = -1 and X= 1 the functions f(x) and g(x) they have the same values.
Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer: Ck.12.org
Step-by-step explanation: Just read the book
