Let us say that the numbers are x and y. The given clues
are:
1. x – y = 16 (so
x is the larger number)
2. y / x = 5 / 7
rewriting eqtn 2 in terms of y:
y = (5/7) x
combining 1 and 2:
x – (5/7) x = 16
(2/7) x = 16
x = 56
y = (5/7) x = 40
So the two numbers are 56 and 40.
If you are given y = (-3/7)x - 2 and you want it in the form Ax+By = C, then...
y = (-3/7)x-2
7*y = 7*( (-3/7)x-2) ... multiply both sides by 7
7y = -3x-14 ... distribute and multiply
7y+3x = -3x-14+3x ... add 3x to both sides
3x+7y = -14
The standard form equation is 3x+7y = -14
The answer to the question is 44 use pemdas
Answer:
7
Step-by-step explanation:
Given the information from the question:
Next we can use the order of operations to find the value of the expression.
Answer:
28
Step-by-step explanation:
Let first integer = x
so second integer = x + 1
according to question we get the equation,,,,
(x) + (x + 1) < 55
x + x + 1 < 55
2x + 1 < 55
subtract 1 from both sides ,we get
2x < 54
divide both sides by 2 we get ......
x < 27
1st integer = x and x < 27
also as we need sum of integer with greates sum so we take x = 26
and 2nd integer = x+1
= 27 + 1
= 28
now if you add both the integers you get sum = 54 which is less than 55 and so this verify you second condtion also .......
hope this will help you
Please feel free to revert back for any further queries.
