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o-na [289]
3 years ago
13

Walter used the iterative process to determine that √13 is between 3.61 and 3.62. Analyze Walter's estimation. Is he correct? If

not, what was his mistake?
Mathematics
2 answers:
nirvana33 [79]3 years ago
5 0

Answer:

yes he is correct

Step-by-step explanation:

Yes, Walter is correct.

No, 3.612 is less than 13.

No, both 3.612 and 3.622 are greater than 13.

No, both 3.612 and 3.622 are less than 13

zavuch27 [327]3 years ago
4 0

Question options:

A. Yes, Walter is correct.

B. No 3.612 is less than 13.

C. No, both 3.612 and 3.622 are greater than

D. No, both 3.612 and 3.622 are less than 13

Answer:

C. No, both 3.612 and 3.622 are greater than the square root of 13

Explanation:

13 is a prime number and must have a decimal number as its square root and so the square root should be between √9 and √16

Using the Newton Raphson method to estimate the square root of 13 with the formula: ai +1= ai²+n/2ai

We get square root of 13 = 3.6055512

This is the same result we get using a calculator to calculate square root of 13= 3.6055512

So yes Walter is not correct

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