Answer:
FF-FF-FF-FF-FF-FF and 255.255.255.255
Explanation:
FF-FF-FF-FF-FF-FF can be defined as the layer 2 address broadcast which is often used on ethernet frames as well as help to broadcast all equipment due to the fact broadcast is made possible through Ethernet networks in which the Frames are addressed to reach every computer system on a given LAN segment as far as they are addressed to MAC address FF:FF:FF:FF:FF:FF.
255.255. 255.255 can be seen as the layer 3 address which help to address the exact same hosts because it enables the broadcast address of the zero network which is the local network due to the fact that the IP broadcasts are often used by BOOTP and DHCP clients to find and send requests to their respective servers in which a message sent to a broadcast address may be received by all network-attached hosts.
Therefore the Layer 2 and Layer 3 destination addresses which the message contain are FF-FF-FF-FF-FF-FF and 255.255.255.255
Answer:
The answer is "Option A".
Explanation:
In the given code an integer array "x" is defined, that stores some elements and another integer variable "a" is declared, that holds a value that is "10". In this code a conditional statement is defined, which checks array element value, in if block element of array that position is 2 is greater then the element of array that position is 5.if this condition is true, so variable a value is change that is equal to 5. In else block if the above condition is not true so the value of a variable is equal to 8, and another options is wrong that can be described as follows:
- In option B, The given condition is not false, that's why it is not correct.
- In option C, The value of variable a is changed when condition is true or false, that's why it is not correct.
- In option D, It is wrong because we can compare array elements.
Given, a = 3, r = 1/2, n = 10
%r is common ratio
%n is number of terms
%a is the first term of the series
Sum = 0;
a = 3;
r = 1/2;
for i = 0 : 1 : 10;
Sum = Sum + a * r ^ i;
end
Sum
Answer:
see attached picture
Explanation:
An algorithm would be:
if hours < 10 then bonus = 0
else if hours <= 15 then bonus = 1000
else if hours <= 20 then bonus = 1500
else if hours <= 25 then bonus = 2000
else if hours <= 30 then bonus = 3000
else bonus = 5000
