Given:
μ = $3.26 million, averaged salary
σ = $1.2 million, standard deviation
n = 100, sample size.
Let x = random test value
We want to determine P(x>4).
Calculate z-score.
z = (x - μ)/ (σ/√n) = (4 - 3.26)/(1.2/10) = 6.1667
From standard tables,
P(z<6.1667) = 1
The area under the distribution curve = 1.
Therefore
P(z>6.1667) = 1 - P(z<=6.1667) = 1 - 1 = 0
Answer: The probability is 0.
They ate 3/8 of the pie because 1/4=2/8 .and 1/8+2/8=3/8. Hope this helps
Answer: The change in temperature each hour was 6 degrees celsius.
Step-by-step explanation: 48 divided by 8 = 6
Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.
This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.
34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
1.9
32 in - 31.2 in
and that to the left of 32 in is z = ---------------------- = 0.421
1.9
Know how to use a table of z-scores to find these two areas? If not, let me know and I'll go over that with you.
My TI-83 calculator provided the following result:
normalcdf(32, 34, 31.2, 1.9) = 0.267 (answer to this sample problem)
