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3 years ago

Write an equation of the line in slope-intercept form.

Mathematics

1 answer:

Tasya [4]3 years ago

6 0

Answer:

y = x + 4

Step-by-step explanation:

From point (-1, 3) to point (0, 4), go up 1 (rise = 1) and go right 1 (run = 1).

slope = m = rise/run = 1/1 = 1

The y-intercept is b = 4

y = mx + b

y = x + 4

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Calculate the answer, express it in scientific notation.

castortr0y [4]

The first one
the first 2 numbers gives a power of 1 then the second gives you 1-4.
1+1-4 is -2 so its the first one

7 0

3 years ago

ZanzabumX [31]

Note that the scale factor of B to A is (4 / 8) = 1/2

So....the volume of B =

Volume of A * (scale factor)^3 =

2720 * (1/2)^3 =

2720 * 1/8 =

340 cm^3

Hope this helps :)

7 0

3 years ago

Read 2 more answers

If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank

strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water ( $Q$ ), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

$Q = \dot Q \cdot \Delta t$ (1)

Where:

$\dot Q$ - Volume rate, measured in feet per minute.

$\Delta t$ - Time, measured in minutes.

If we know that $\dot Q = 2000\,\frac{gal}{min}$ and $\Delta t = 120\,min$ , then the amount of water is:

$Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)$

$Q = 32160\,ft^{3}$

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot h$ (2)

Where:

$D$ - Diameter, measured in feet.

$h$ - Height, measured in feet.

If we know that $Q = 32160\,ft^{3}$ and $h = 12\,ft$ , then the minimum diameter is:

$D^{2} = \frac{4\cdot Q}{\pi\cdot h}$

$D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }$

$D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }$

$D \approx 58.415\,ft$

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0

3 years ago

Please help me! Thanks.

Vedmedyk [2.9K]

Answer:

129 is yr ANSWER........

5 0

4 years ago

Read 2 more answers

Simplify this expression

pishuonlain [190]

Answer:

After simplifying, the exponent of x is 33 and the exponent of y is 0

Step-by-step explanation:

For us to simplify, we bring the x base together and the y base together

Recall from the law of indices;

x^a/x^b = x^(a-b)

and x^a * x^b = x^(a + b)

We shall be applying these here

Let us bring the x terms together

we have these as;

x^8/x^14 * 1/x^-39 = x^( 8 - 14 -(-39))

= x^(8 + 39-14) = x^33

for y, we have it that;

y^-26/y^-5 * 1/y^-21

= y^(-26 -(-5) - (-21)

= y^-26 + 5 + 21 = y^0

8 0

3 years ago