2+3/5x-1-1/4x
2+3x-1/5-1-x/5
2+3/5x-1-x/5
1+3/5x-x/5
1+2/5x
To put an equation into (x+c)^2, we need to see if the trinomial is a perfect square.
General form of a trinomial: ax^2+bx+c
If c is a perfect square, for example (1)^2=1, 2^2=4, that's a good indicator that it's a perfect square trinomial.
Here, it is, because 1 is a perfect square.
To ensure that it's a perfect square trinomial, let's look at b, which in this case is 2.
It has to be double what c is.
2 is the double of 1, therefore this is a perfect square trinomial.
Knowing this, we can easily put it into the form (x+c)^2.
And the answer is: (x+1)^2.
To do it the long way:
x^2+2x+1
Find 2 numbers that add to 2 and multiply to 1.
They are both 1.
x^2+x+x+1
x(x+1)+1(x+1)
Gather like terms
(x+1)(x+1)
or (x+1)^2.
Hey can someone help me with my latest question no one‘s helping me and I really need it
Answer:
The slope is 3/2 and the y intercept is 4
Step-by-step explanation:
We want to write in the form
y = mx+b where m is the slope and b is the y intercept
-3x+2y = 8
Add 3x to each side
-3x+3x+2y = 3x+8
2y = 3x+8
Divide each side by 2
2y/2 = 3x/2 + 8/2
y = 3/2x +4
The slope is 3/2 and the y intercept is 4
