Ask question

Ask question

All categories

3 years ago

10

Please answer this like I

1 answer:

White raven [17]3 years ago

8 0

roses are red violets are blue my heart is dead im such a fool

You might be interested in

-6x + 5y = 1<br> 6x + 4y = –10

Firlakuza [10]

Answer:

x=-1

y=-1

Step-by-step explanation:

-6x + 5y =1 ......equation (1)

6x + 4y = –10 ......equation (2)

adding equation (1) to equation (2)

9y=-9

9y/9 =-9/9 (dividing both side by the coefficient of y)

y=-1

subtituting the value of y =-1 into equation (2)

6x+4(-1)=-10

6x+(-4)=-10

6x-4=-10

6x=-10+4(making constant to be at one side and the variable at the other side)

6x=-6

x=-6/6

x=-1

8 0

3 years ago

Homework is boring ..... ugh

Vladimir [108]

Answer:

Yes, it is.

Step-by-step explanation:

ALSO, YO THANK YOU FOR GETTING ME TO GENIUS.

8 0

2 years ago

Read 2 more answers

PLEASE HELP!! 25 POINTS!! REALLY!!!

Snezhnost [94]

Reflex angle.
hope this helped!

3 0

2 years ago

Read 2 more answers

Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions

quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of $v_0$ and $F_2$ be the component normal to $v_0$ .

Since, $|v_0| = 1,$

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, $v_0 = \left$

From figure,

$|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3$

We know that the direction of $F_1$ is opposite of the direction of $v_0$ , so we have

$F_1 = -5\sqrt3 v_0$

$=-5\sqrt3 \left$

$= \left$

The unit vector in the direction normal to the plane, $v_1$ has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

$|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5$

∴ $F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>$

$=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

$= = F$

3 0

2 years ago

Please give answers for #1, #2, #3, and #4 please help <br> ill mark brainliest.

Ira Lisetskai [31]

Answer:

Find y output

Step-by-step explanation:

Just took test

5 0

2 years ago