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3 years ago

7

bonnie has just received an order for a square frame that has 102 tiles along each side.how many tikes will she need to make thi

s frame? Explain how you got your awnswer

2 answers:

Ray Of Light [21]3 years ago

6 0

102 times 4 =408

i know this because a square has 4 sides and i just need to multiply 102 and 4

DerKrebs [107]3 years ago

5 0

The answer is 408 because I did it on a piece of paper

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The coffee cup can hold 7/9 of a pint of liquid. If Emily pours 2/3 of a pint of coffee into a cup, how much more milk can she a

Orlov [11]

1/9 pints of milk can be added by a customer

Step-by-step explanation:

We have to subtract simple fractions to find the amount of milk that can be added to a cup of coffee

Given

Total Capacity of a cup = 7/9 pints

Coffee to be added in a cup = 2/3 pints

So in order to find the amount of milk that can be added we have to subtract the amount of coffee from the total capacity of cup.

So,

Hence,

1/9 pints of milk can be added by a customer

Keywords: Fractions, addition

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Carlos has 24 balls of different colors: yellow, red, green, and blue. 17 balls are not red,10 balls are neither yellow nor blue

olga55 [171]

Answer:

10 green

Step-by-step explanation:

24 total balls. 17 Not red, so 24-17=7. 7 Red balls. That leaves 17 balls. 10 of them are neither yellow nor blue, and since the amount of red balls has been figured out, we do not need to account for them. 17 balls - 10 not yellow or blue equals 7 balls that can be yellow or blue. 17 balls left, minus the 7 yellow or blue balls equals 10.

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2 years ago

A kite flier wondered how high her kite was flying. She used a protractor to measure an angle of 15∘ from level ground to the ki

Nataly [62]

Answer:

12.9 yd

Step-by-step explanation:

It helps if you draw a triangle. Draw a horizontal segment. That is the ground. Now at the left end start a new segment that goes up to the right at approximately 15 degrees until it its other endpoint directly above the right endpoint of the horizontal segment. Connect these two endpoints. The vertical side on the right shows the height of the kite. The hypotenuse is the string.

For the 15-deg angle, the height of the triangle is the opposite leg, and the string is the hypotenuse. The trig ratio that relates the opposite leg tot he hypotenuse is the sine.

$\sin A = \dfrac{opp}{hyp}$

$\sin 15^\circ = \dfrac{h}{50~yd}$

$(50~yd)\sin 15^\circ = h$

$h = (50~yd)(0.2588)$

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3 years ago

34% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

10 student are sampled, so $n = 10$

34% of college students say they use credit cards because of the rewards program, so $\pi = 0.34$

(a) exactly two

This is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than two

This is $P(X > 2)$ .

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

$P(X \leq 2) + P(X > 2) = 1$

$P(X > 2) = 1 - P(X \leq 2)$

In which

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

So

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157$

$P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838$

$P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162$

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

$P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

$P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573$

$P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320$

$P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434$

$P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82$

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0

3 years ago