If the directions were given to translate a shape (x+7, y-3) describe how the shape would move.

Mathematics

1 answer:

Sindrei [870]3 years ago

8 0

Answer: move 7 places to the right and 3 places down

Step-by-step explanation:

You might be interested in

Which expression is equivalent to 6m+(m-2)(m+7)+3

Vika [28.1K]

Answer:

$m^{2}$ + 11m - 11

Step-by-step explanation:

6m+(m-2)(m+7)+3 = 6m + [ m*m - 14 -2m + 7m] + 3

= 6m + mm - 14 + 5m + 3

= mm + 11m - 11

6m+(m-2)(m+7)+3 = $m^{2}$ + 11m - 11

5 0

3 years ago

Write the standard form of the equation of the circle with the given characteristics. Center: (3, 5); Solution point: (−2, 17)

Angelina_Jolie [31]

$\text{we know that the general equation of the circle is }\\
\\
(x-h)^2+(y-k)^2=r^2\\
\\
\text{where, (h,k) is the center of the circle and r is the radius.}\\
\\
\text{Given that the centered of the circle is at }(h,k)=(3,5)\\
\text{and a solution point on circle is (-2,17).}\\
\\
\text{so the radius of the circle will be the distance between center and the }$

$\text{solution point. so using the distance formula, we have}\\
\\
\text{Radius, }r=\sqrt{(-2-3)^2+(17-5)^2}\\
\\
\Rightarrow r=\sqrt{25+144}\\
\\
\Rightarrow r=\sqrt{169}\\
\\
\Rightarrow r=13\\
\\
\text{Hence using the standard for of circle, equation of circle with center}\\
(h,k)=(3,5) \text{ and radius r=13 is}\\
\\
(x-3)^2+(y-5)^2=(13)^2\\
\\
\Rightarrow (x-3)^2+(y-5)^2=169$