B = 4
A line with a slope of zero is a perfectly horizontal line, which means the y value (the second value) stays the same for every single point on the line.
So, if y equals 4 in the first point, then y still equals 4 in the second point, which means b is equal to 4.
The formula for an exponential equation is y = a * b^x with a and b being a fixed value.
"a" would also be the Y intercept, which is where the graph touches or crosses the Y axis. In the given graph, the curved line touches the Y axis at 100, so the value of a would be 100.
Now we need to find b.
The blue dot at Y 50 is lined up with x = 1, so we can use the point (1,50)
Using the X and Y values we can solve for b:
format: y = a * b^x we replace the letters with the numbers above:
50 = 100 * b^1
b^1 = b so now we have:
50 = 100 *b
Divide both sides by 100 to get b by itself:
b = 50/100, which reduces to 1/2, so b = 1/2
So the equation of the graph becomes y = 100(1/2)^x
You may need to write the 1/2 as 0.5, not sure how you need to enter it.
Suppose that the height (in centimeters) of a candle is a linear function of
the amount of time (in hours) it has been burning.
Let x be the amount of time in hours
Let y be the heoght of a candle in centimeters
The two points are then as (9,24.5) and (23,17.5).














Now plug in x=21, we get

Thus the height of the candle after 21 hours is 18.5 centimeters.
Answer:
y=-x
Step-by-step explanation:
It's going left one by one, meaning the slope is negative and has a slope of -1 or -x.
A 3d cardboard box has 6 sides, each of which are rectangles. If you unfold the 3D box, and flatten it out, then you'll be left with 6 rectangles such as what you see in the attachment below. This is one way to unfold the box. This flattened drawing is the net of the 3D rectangular prism. You can think of it as wrapping paper that covers the exterior of the box. There are no gaps or overlapping portions. If you can find the area of each piece of the net, and add up those pieces, that gets you the total area of the net. This is the exactly the surface area of the box.
In the drawing below, I've marked the sides as: top, bottom, left, right, front, back. This way you can see how the 3D box unfolds and how the sides correspond to one another. Other net configurations are possible.