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Dafna1 [17]
3 years ago
11

1/3h-4(2/3h-3)=2/3h-6

Mathematics
2 answers:
Likurg_2 [28]3 years ago
6 0
H is 6. If you are not familiar with /3 you could time the whole equation by 3
tino4ka555 [31]3 years ago
4 0
(1/3)*h-(4*((2/3)*h-3)) = (2/3)*h-6 // - (2/3)*h-6

(1/3)*h-(4*((2/3)*h-3))-((2/3)*h)+6 = 0

(1/3)*h-4*((2/3)*h-3)+(-2/3)*h+6 = 0

h/3-4*(2/3*h-3)+(-2*h)/3+6 = 0

(-4*3*(2/3*h-3))/3+h/3+(-2*h)/3+(3*6)/3 = 0

h-4*3*(2/3*h-3)-2*h+3*6 = 0

18-7*h-2*h+36 = 0

18-9*h+36 = 0

54-9*h = 0

(54-9*h)/3 = 0

(54-9*h)/3 = 0 // * 3

54-9*h = 0

54-9*h = 0 // - 54

-9*h = -54 // : -9

h = -54/(-9)

h = 6

h = 6
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A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height
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Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

y(t)=43t-23t^{2}

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\displaystyle\frac{\text{Displacement}}{\text{Time}}

1) 0.01

y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}

2) 0.005 s

y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}

3) 0.002 s

y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}

4) 0.001 s

y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}

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Find the x- and y-intercepts of the function f(x) = log(2x + 1) − 1.
zaharov [31]

Answer:

The y-intercept is -1

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Step-by-step explanation:

We have the following equation:

f(x) = log(2x+1) - 1

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