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Dafna1 [17]
4 years ago
11

1/3h-4(2/3h-3)=2/3h-6

Mathematics
2 answers:
Likurg_2 [28]4 years ago
6 0
H is 6. If you are not familiar with /3 you could time the whole equation by 3
tino4ka555 [31]4 years ago
4 0
(1/3)*h-(4*((2/3)*h-3)) = (2/3)*h-6 // - (2/3)*h-6

(1/3)*h-(4*((2/3)*h-3))-((2/3)*h)+6 = 0

(1/3)*h-4*((2/3)*h-3)+(-2/3)*h+6 = 0

h/3-4*(2/3*h-3)+(-2*h)/3+6 = 0

(-4*3*(2/3*h-3))/3+h/3+(-2*h)/3+(3*6)/3 = 0

h-4*3*(2/3*h-3)-2*h+3*6 = 0

18-7*h-2*h+36 = 0

18-9*h+36 = 0

54-9*h = 0

(54-9*h)/3 = 0

(54-9*h)/3 = 0 // * 3

54-9*h = 0

54-9*h = 0 // - 54

-9*h = -54 // : -9

h = -54/(-9)

h = 6

h = 6
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3 years ago
Four circles of unit radius are drawn with centers $(1,0)$, $(-1,0)$, $(0,1)$, and $(0,-1)$. a circle with radius 2 is drawn wit
Reika [66]
Check the picture 1.

The regions contained in an odd number of these 5 circles are

the pink colored region, contained only in the circle with radius 2, 

and the yellow regions, each contained in the intersection of 2 small circles and the third large circle.

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Consider the second picture.

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the region A2 + A1 is called a sector, and it is 1/4 of the area of a unit circle.

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The purple area is:
 
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A_{purple}=\pi.2^2-4(\pi.1^2)+2\pi-4=4\pi-4\pi+2\pi-4=2\pi-4


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Answer:   6\pi-8    square units

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Ierofanga [76]

Answer:

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